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Anna [14]
3 years ago
9

Solve the logarithmic equation. Be sure to reject any value of x that is not in the domain of the original logarithmic expressio

ns. Give the exact answer
In (x - 2) - In (X + 8) = In (x - 1) - In (x + 12)
Rewrite the given equation without logarithms. Do not solve for x
Solve the equation to find the solution set. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
O A. The solution set is { }
(Type an integer or a simplified fraction Use a comma to separate answers as needed)
OB. There are infinitely many solutions
O C. There is no solution
Mathematics
2 answers:
Sidana [21]3 years ago
8 0

9514 1404 393

Answer:

  x = 16/3

Step-by-step explanation:

a) The rewritten equation is ...

  \dfrac{x-2}{x+8}=\dfrac{x-1}{x+12}

__

b) The solution can be found as ...

  \dfrac{x-2}{x+8}-\dfrac{x-1}{x+12}=0\\\\(x-2)(x+12)-(x+8)(x-1)=0 \qquad\text{numerator of the difference}\\\\(x^2+10x-24)-(x^2+7x-8)=0\\\\3x-16=0\qquad\text{simplified}\\\\x=\dfrac{16}{3}\qquad\text{one solution}

The solution set is {16/3}.

_____

The applicable rule of logarithms is ...

  log(a) -log(b) = log(a/b)

Crank3 years ago
3 0

Answer:

the answer is x=16/3

Step-by-step explanation:

:))

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A soda bottling company’s manufacturing process is calibrated so that 99% of bottles are filled to within specifications, while
bija089 [108]

Answer:

The probability that the assembly line will be shut down is 0.00617.

Step-by-step explanation:

We are given that a soda bottling company’s manufacturing process is calibrated so that 99% of bottles are filled to within specifications, while 1% is not within specification.

Every hour, 12 random bottles are taken from the assembly line and tested. If 2 or more bottles in the sample are not within specification, the assembly line is shut down for recalibration.

Let X = <u><em>Number of bottles in the sample that are not within specification</em></u>.

The above situation can be represented through binomial distribution;

P(X=r)=\binom{n}{r} \times p^{r}\times (1-p)^{n-r};x=0,1,2,3,.....

where, n = number of trials (samples) taken = 12 bottles

             x = number of success  = 2 or more bottles

            p = probabilitiy of success which in our question is probability that  

                 bottles are not within specification, i.e. p = 0.01

So, X ~ Binom (n = 12, p = 0.01)

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  P(X \geq 2) = 1 - P(X = 0) - P(X = 1)

                 = 1-\binom{12}{0} \times 0.01^{0}\times (1-0.01)^{12-0}-\binom{12}{1} \times 0.01^{1}\times (1-0.01)^{12-1}

                 = 1-(1 \times 1\times 0.99^{12})-(12 \times 0.01^{1}\times 0.99^{11})

                 = <u>0.00617</u>

8 0
3 years ago
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