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Elden [556K]
3 years ago
12

An underlying theme of astronomy is that the...

Physics
1 answer:
amm18123 years ago
3 0

Answer:

d) entire universe is governed by a single set of fundamental physical laws.

Explanation:

Astronomy is the field of study that researches and studies about the objects beyond Earth. The phenomena occurring in the universe and their effects on the planet Earth are all death under the subject of astronomy. The discovery and the origin of the Earth, the heavenly bodies and their existence are covered under astronomy. The fundamental laws of the astronomy proves to be equivalent for all the bodies. These laws are universal that helps in the research of the science of universe.

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how height does a 2.5 Kg object rises when 255J of work done against gravity A 637.5 B 20.5 C 15m D 10.2 m​
balu736 [363]

Answer:

D 10.2

Explanation:

255 ÷ 2.5= 10.2 or D

7 0
3 years ago
Read 2 more answers
How do we know that caramelizing sugar is a chemical change? A. It involves dissolving sugar in water. B. It changes the state o
amid [387]

Answer:

I think the correct answer is c

8 0
3 years ago
A horizontal string fixed at both ends is oscillating in a standing wave pattern. Consider the vertical motion of a point on the
Naddika [18.5K]

Answer:

All of the choices are correct except the nodes, which don't move at all.

Explanation:

when a horizontal string fixed at both ends is oscillating in a standing wave pattern the antinodes move with simple harmonic motion while the node is stationary.  

6 0
3 years ago
A 0.290 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 30.0 pC charge on it
mojhsa [17]

Answer:

Therefore,

The potential (in V) near its surface is 186.13 Volt.

Explanation:

Given:

Diameter of sphere,

d= 0.29 cm

radius=\dfrac{d}{2}=\dfrac{0.29}{2}=0.145\ cm

r = 0.145\ cm = 0.145\times 10^{-2}\ m

Charge ,

Q = 30.0\ pC=30\times 10^{-12}

To Find:

Electric potential , V = ?

Solution:

Electric Potential at point surface is given as,

V=\dfrac{1}{4\pi\epsilon_{0}}\times \dfrac{Q}{r}

Where,  

V= Electric potential,  

ε0 = permeability free space = 8.85 × 10–12 F/m

Q = Charge  

r = Radius  

Substituting the values we get

V=\dfrac{1}{4\times 3.14\times 8.85\times 10^{-12}}\times \dfrac{30\times 10^{-12}}{0.145\times 10^{-2}}

V=\dfrac{30}{16.117\times 10^{-2}}=186.13\ Volt

Therefore,

The potential (in V) near its surface is 186.13 Volt.

3 0
3 years ago
What is the correct answer?
alina1380 [7]

Answer:

4

Explanation:

I added all of them and them minus the 5.

8 0
2 years ago
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