Answer:
6.19 x m/
Explanation:
For this exercise we need to sum the forces on the y-axis and x-axis as follows:
∑ = N - mg = m. = 0
From the exercise, we deduce there is no motion in y-axis, so:
N = mg
Then for x-axis we have:
∑ = H - = m. = 0
Now, from the exercise we deduce that we are looking for the greatest static friction which means to have the maximun static friction to start moving, so at this point the acceleration is zero, so we can find horizontal force (H), which then will act in the airplane to move it. Therefore we have:
H = = = N = mg
H = (0.76)(84Kg)(9.8m/)
H = 625.63 N
Now we apply this force to the weight of the plane to find the greatest acceleration the mann can give to start moving the plane.
a = =
a =
a = 6.19 x m/
8.854 m/s is the speed of the box after it reaches bottom of the ramp.
<u>Explanation</u>:
From the figure we came to know that height of the block is 4 m.
We know that,
Total "initial energy of an object" = Total "final energy of an object
"
Total "initial energy of an object" is = "sum of potential energy" and "kinetic energy" of an object at its initial position.
Initial velocity is “0” as the object does not have starting speed
Total initial energy = 39.2 × m
Now, Total initial energy of an object = Total final energy of an object
Final speed is 8.854 m/s.
What well u can use to make a shelter but that's all I can think of ??
;Net force = mass of the body × acceleration of the body due to the net force
; 5000 = 2500 a...then divide both sides by 2500
; acceleration(a) = 2 m/s^2