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mash [69]
3 years ago
10

In circle D with m \angle CDE= 60m∠CDE=60 and CD=3CD=3 units, find the length of arc CE. Round to the nearest hundredth

Mathematics
1 answer:
krok68 [10]3 years ago
3 0

Answer:

Length of arc CE = 3.14 unit (Approx.)

Step-by-step explanation:

Given:

Radius of circle = 3 units

Angle between radius = 60°

Find:

Length of arc CE

Computation:

Length of arc = [θ/360][2πr]

Length of arc CE = [60/360][2(2/7)(3)]

Length of arc CE = [60/360][2(3.14)(3)]

Length of arc CE = [1/6][6(3.14)]

Length of arc CE = 3.14 unit (Approx.)

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Answer:

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Step-by-step explanation:

no number of tanks will hold the same amount of fish. 83 is a prime number, no numbers can be equally divided into it

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A line has x-intercept of 6 and y-intercept of -4.Find the slope of the line.
Zigmanuir [339]

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3 years ago
An 8 by 19 ft wall has three 4 by 5ft windows. The area of three windows is what percent of the area of the entire wall
sergij07 [2.7K]
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6 0
3 years ago
Can some one help me
il63 [147K]

Answer:

5/6

Step-by-step explanation:

<em>Dividing fractions:</em>

<em>Step 1: Rewrite the first fraction as it is.</em>

<em>Step 2: Replace the division sign with a multiplication sign.</em>

<em>Step 3: Flip the second fraction.</em>

<em>Step 4: Multiply the fractions and reduce the product if necessary.</em>

Let's use the rule of dividing fractions on your problem.

Step 1: Rewrite the first fraction as it is.

\dfrac{5}{8}

Step 2: Replace the division sign with a multiplication sign.

\dfrac{5}{8} \times

Step 3: Flip the second fraction.

\dfrac{5}{8} \times \dfrac{4}{3}

Step 4: Multiply the fractions and reduce the product if necessary.

To multiply fractions, multiply the numerators together, and multiply the denominators together.

\dfrac{5}{8} \times \dfrac{4}{3} = \dfrac{5 \times 4}{8 \times 3} = \dfrac{20}{24}

We notice that the greatest common factor of 20 and 24 is 4, so we divide both the numerator and denominator by 4 to reduce the fraction.

= \dfrac{4 \times 5}{4 \times 6} = \dfrac{5}{6}

5 0
3 years ago
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