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telo118 [61]
3 years ago
5

Just give me a RIGHT ANSWER please lol...

Mathematics
1 answer:
alisha [4.7K]3 years ago
4 0
12 mph mphhhhhh LET ME SEND
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HAI HELP ME ASAP PLEASE
11111nata11111 [884]

Answer:

Y/X = 2/3 x^2 + 16/3

Y= 2/3 x^3 + 16/3 x

Just replace y with y/X and X with x^2

7 0
3 years ago
(3x^2+2x-3)(x-1)<br> please help
cupoosta [38]

Answer:

Step-by-step explanation:

(3x^2 + 2x - 3)(x-1)

Expanding the brackets

x(3x^2 +2x - 3) -1(3x^2 +2x -3)

3x^3 +2x^2 -3x -3x^2 -2x + 3

3x^3 - x^2 - 5x + 3

5 0
3 years ago
Don't mind the writings in pen, i didn't know what i was doing... PLS HELP ASAP​
Serjik [45]

Answer:

(a) <AED=50°

(b) <DAB=65°

(c) <BCD=45°

(d) Reflex <ABC=225°

Step-by-step explanation:

(a) 180-65-65=50

(b) 180-115=65 (ADC is 115)

(c) 180-135-45

(d) Reflex <ABC 360-135=225

7 0
3 years ago
Can someone help me with these two
Leviafan [203]

Answer: I believe it is D..

3 0
3 years ago
Please explain how to do and set up
In-s [12.5K]

A

using the Cosine rule in ΔSTU

let t = SU, s = TU and u = ST, then

t² = u² + s² - (2us cos T )

substitute the appropriate values into the formula

t² = 5² + 9² - (2 × 5 × 9 × cos68° )

   = 25 + 81 - 90cos68°

   = 106 - 33.71 = 72.29

⇒ t = \sqrt{72.29} ≈ 8.5 in → A


6 0
3 years ago
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