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2 years ago

Phase difference formula

Physics

1 answer:

Anestetic [448]2 years ago

3 0

Answer:

Δx is the path difference between the two waves.

...

Phase Difference And Path Difference Equation.

Formula Unit

Phase Difference \Delta \phi=\frac{2\pi\Delta x}{\lambda } Radian or degree

Path Difference \Delta x=\frac{\lambda }{2\pi }\Delta \phi meter

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I wish to use a step up transformer to turn an initial RMS AC voltage of 100 V into a final RMS AC voltage of 200 V. What is the

zhuklara [117]

Answer:

1:2

Explanation:

It is given that,

Initial RMS AC voltage is 100 V and final RMS AC voltage is 200 V.

We need to find the ratio of the number of turns in the primary to the secondary for step up transformer.

For a transformer, $\dfrac{V_1}{V_2}=\dfrac{N_1}{N_2}$

So,

$\dfrac{N_1}{N_2}=\dfrac{100}{200}\\\\\dfrac{N_1}{N_2}=\dfrac{1}{2}$

So, the ratio of the number of turns in the primary to the secondary is 1:2.

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3 years ago

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LuckyWell [14K]

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2. Social justice

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4. Integrity

5. Competence.

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3 years ago

A baseball bat balances 74.9 cm from one end. If an 0.560-kg glove is attached to that end, the balance point moves 25.3 cm towa

timurjin [86]

Answer:

The mass of the bat is 1.09 kg.

Explanation:

Given that,

The balance point of the glove, x = 74.9 cm

Mass of the glove, m = 0.56 kg

Center of mass of the baseball bat, C = 25.3 cm

Let M is the mass of the bat. The center of mass is given by the formula as :

$C=\dfrac{MX+mx}{M+m}$

X is 0 as it is at a end

$C=\dfrac{mx}{M+m}$

$25.3=\dfrac{0.56\times 74.9}{M+0.56}$

M = 1.09 kg

So, the mass of the bat is 1.09 kg. Hence, this is the required solution.

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3 years ago

What is the weight of a pumpkin with a mass of 5 kg? kk

pav-90 [236]

Explanation:

actually, the question would need to give you what is the gravitational force, so let's take the average of the gravitational for me which is 10 N /kg

and the formula for finding weight is

W = mg

W = (5)(10)

W = 50 N

hope it is helpful, if not please report it so that someone else gets to try

please vote

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2 years ago

A ball droped from a building. How fast is it traveling after falling 3.55s

algol [13]

Answer:

d = 61.75 m

Explanation:

Given that,

A ball droped from a building.

We need to find how fast is it traveling after falling 3.55 s.

As it is dropped, its initial velocity is equal to 0.

Let d is the distance it covers after falling 3.55 s.

We can use second equation of motion to find d.

$d=ut+\dfrac{1}{2}at^2$

Here, u = 0 and a =g

$d=\dfrac{1}{2}gt^2\\\\d=\dfrac{1}{2}\times 9.8\times (3.55)^2\\\\d=61.75\ m$

So, it will cover 61.75 m after falling 3.55 seconds.

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3 years ago