Answer is
9.773m/s^2
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Given,
h=8848m
The value of sea level is 9.08m/s^2. So, Let g′ be the acceleration due to the gravity on Mount Everest.
g′=g(1 − 2h/h)
=9.8(1 - 6400000/17696)
=9.8(1 − 0.00276)
9.8×0.99724
=9.773m/s^2
Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s^2
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hope this helps :)
Answer:
125.5J
Explanation:
Given parameters:
Mass of the bowling ball = 6.1kg
Height of lifting = 2.1m
Unknown:
Increase in the ball energy = ?
Solution:
The ball has changed position by moving it from one point to another. So, it has acquired more potential energy.
Potential energy = mgh
m is the mass
g is the gravity
h is the height
Now insert the given parameters and solve;
Potential energy = 6.1 x 9.8 x 2.1 = 125.5J
Answer:
Explanation:
Consider downward displacement first .
downward displacement h = 38 m .
downward acceleration = g
downward initial velocity u = 0
h = ut + 1/2 g t ²
38 = 0 + 9.8 t ²
t = 1.97 s
During this period , there will be horizontal displacement with initial velocity u = 10 m /s and acceleration a = 1.6 m /s²
s = ut + 1/2 a t²
= 10 x 1.97 + .5 x 1.6 x 1.97²
= 19.7 + 3.10
= 22.8 m
Hello.
The answer is <span>C) as carbon dioxide.
Have a nice day </span>
