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kirill [66]
4 years ago
12

Complete the following sentences. a. The motion of the particles is a model of__________. . b. The movement of particles from on

e chamber to another is a model of________. . c. When the average motion of the particles is the same in both chambers, this is a model of _______.
Physics
1 answer:
Leno4ka [110]4 years ago
8 0
Effectiv was the morning time to go home
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A worker lifts a 20.0-kg bucket of concrete from the ground up to the top of a 25.0-m tall building. The bucket is initially at
yuradex [85]

Answer:

Minimum work = 5060 J

Explanation:

Given:

Mass of the bucket (m) = 20.0 kg

Initial speed of the bucket (u) = 0 m/s

Final speed of the bucket (v) = 4.0 m/s

Displacement of the bucket (h) = 25.0 m

Let 'W' be the work done by the worker in lifting the bucket.

So, we know from work-energy theorem that, work done by a force is equal to the change in the mechanical energy of the system.

Change in mechanical energy is equal to the sum of change in potential energy and kinetic energy. Therefore,

\Delta E=\Delta U+\Delta K\\\\\Delta E= mgh+\frac{1}{2}m(v^2-u^2)

Therefore, the work done by the worker in lifting the bucket is given as:

W=\Delta E\\\\W=mgh+\frac{1}{2}m(v^2-u^2)

Now, plug in the values given and solve for 'W'. This gives,

W=(20\ kg)(9.8\ m/s^2)(25\ m)+\frac{1}{2}(20\ kg)(4^2-0^2)\ m^2/s^2\\\\W=4900\ J +160\ J\\\\W=5060\ J

Therefore, the minimum work that the worker did in lifting the bucket is 5060 J.

7 0
3 years ago
what is the mass of an object that needs a force of 6600N to increase its speed from rest to 107 m/s in 2.3 seconds
Ray Of Light [21]
To answer this question do you need to know the formula to get the rate of change of acceleration (a=Δv/Δt; Δv= final velocity - initial velocity) and the formula to find the force of an object given a constant acceleration (F=m*a). Given these two formulas you can applicate them to solve for the mass of an object.

6 0
3 years ago
Two blocks of masses m1 and m2 are connected to each other on an Atwood machine (the blocks are connected by a string going over
ddd [48]

Answer:211.11 gm

Explanation:

Given

mass of lighter block m_1=100 gm

mass of heavier  block is m_2

acceleration of system a=3.5 m/s^2

From diagram

for lighter block

T-m_1g=m_1a

T=m_1(g+a)

For heavier Block

m_2g-T=m_2a

T=m_2(g-a)

Equating Tension T

m_1(g+a)=m_2(g-a)

m_2=m_1\cdot \frac{g+a}{g-a}

m_2=m_1\cdot \frac{9.8+3.5}{9.8-3.5}

m_2=0.1\cdot 2.11

m_2=0.2111 kg

m_2=211.11 gm

8 0
3 years ago
HELP
svet-max [94.6K]

Answer:

Cold Front 3  //  Stationary Front 1  //  Warm Front 2  //  Occluded Front 4

Explanation:

It's simple.  Warm front means the warm air is pressing forward,  which is why it's a warm front.  Stationary Front, meaning they're at a standstill, also makes sense because stationary means not moving.  Then since your last option is Occluded Front, since the others already have an answer, you have no choice but to match 4 with it.  I took the quiz and got the answer right.  :D

6 0
3 years ago
Explain which of the following has more inertia and why: a 200 lb wrestler sitting on a mat or a baseball flying through the air
Wittaler [7]

Inertia is the property of mass and as per the definition of inertia we can say that object will continue its state of motion and resist any change in its state of motion due to inertia

Inertia is only the property of mass and no other physical quantity can change the inertia of object

So it is directly proportional to the mass of the object

So if object has more mass then it will have more inertia

in this given example we have to compare the inertia of a 200lb wrestler and a baseball

So here the speed of baseball is of no use as inertia can not be determined by speed of the ball

Since here mass of the wrestler is more so his inertia will be more than the inertia of baseball


7 0
4 years ago
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