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kirill [66]
4 years ago
12

Complete the following sentences. a. The motion of the particles is a model of__________. . b. The movement of particles from on

e chamber to another is a model of________. . c. When the average motion of the particles is the same in both chambers, this is a model of _______.
Physics
1 answer:
Leno4ka [110]4 years ago
8 0
Effectiv was the morning time to go home
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A 0.614mole sample of ideal gas at 12degree occupies a volume of 4.32.what is the pressure of the gas
Kaylis [27]

Answer:

336.9520 atm

Explanation:

The Gas Equation is as follows;-

Pressure×Volume=Number of Moles × Universal Gas Constant ×Temperature(in Kelvin)

Given Parameters

Number of moles-0.614 mol

Temperature 12°C or 12+273.15 ie 285.15°F

Volume-4.32 L

Universal Gas Constant-8.314 J/mol·K

Pressure -?(in atm)

Plugging in all the values in the Gas Equation:-

Pressure=\frac{0.614 × 8.314× 285.15}{4.32}   atm

Pressure=336.9520 atm

3 0
3 years ago
A 60 kg gorilla named Anthony Falcon is standing on his skateboard. This is on planet Erf,
djyliett [7]
F= ma
F= (600/-10) -10
F= 580n

At least I think that’s the answer
4 0
2 years ago
Is a pair of sneakers a want or a need? Is the most expensive pair of sneakers a want or a need?
IgorLugansk [536]

Explanation: A sneaker is a want because you don't actually need it to survive

8 0
3 years ago
The bonds of oxygen molecules are broken by sunlight. The minimum energy required to break the oxygen-oxygen bond is 495 kJ/mol.
makvit [3.9K]

Answer:

The wavelength of sunlight that can cause this bond breakage is 242 nm

Explanation:

The minimum energy of the sunlight that'll break Oxygen-oxygen bond must match 495 KJ/mol

But 1 mole of any molecule contains 6.02 × 10²³ molecules/mol

Each molecule of Oxygen will require (495 × 10³)/(6.02 × 10²³) = 8.22 × 10⁻¹⁹ J

E = hf

v = fλ

f = v/λ

f = frequency of the sunlight

λ = wavelength of the sunlight

v = speed of light = 3.0 × 10⁸ m/s

E = hv/λ

λ = hv/E

h = Planck's constant = 6.63 × 10⁻³⁴ J.s

λ = (6.63 × 10⁻³⁴)(3 × 10⁸)/(8.22 × 10⁻¹⁹)

λ = 2.42 × 10⁻⁷ m = 242 nm.

5 0
3 years ago
A truck traveled 400 meters north in 80 seconds and then it traveled 300 meters east in 70 seconds. The magnitude of the average
Varvara68 [4.7K]

Answer:

3.3m/s

Explanation:

You first get the total time (80 + 70 = 150s).

Then you would find the displacement of the truck. To do that you would do component method (vector addition), so since its a right triangle (North and East), displacement is 400^2 + 300^2 = d^2.

d= 500m.

So now that you have displacement and time, you can find the velocity:

v=d/t

v=500/150

v=3.3

5 0
3 years ago
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