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disa [49]
3 years ago
6

What is a nonzero net force called

Physics
2 answers:
eduard3 years ago
6 0

Equilibrium.

• When an object is in equilibrium (either at rest or moving with constant velocity), the net force acting on it zero.

olasank [31]3 years ago
5 0

Answer:

Equilibrium. • When an object is in equilibrium (either at rest or moving with constant velocity), the net force acting on it zero. 

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A soccer ball was kicked . it had the mass of .42 kg and accelerated at 25m/s . what was the force?
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A 17 kg box sitting on a shelf has a potential energy of 350 J. How high is the shelf? Round your answer to the nearest whole nu
Free_Kalibri [48]
Potential energy is mass * gravity * height. (m*g*h).

350 = 17*9.8*h   <--350 is its energy, 17kg is its mass, and 9.8 is gravity's acceleration on the object. We now just need to solve for h.

h = 350/(17 * 9.8) =  2.1 meters, which, when rounded to the nearest whole meter, is 2 meters.

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3 years ago
Two flat surfaces are exposed to a uniform, horizontal magnetic field of magnitude 0.47 T. When viewed edge-on, the first surfac
alexgriva [62]

Answer:

a. A = 0.0859 m^2

b. A = 0.0178 m^2

Explanation:

Two flat surfaces are exposed to a uniform, horizontal magnetic field of magnitude 0.47 T. When viewed edge-on, the first surface is tilted at an angle of from the horizontal, and a net magnetic flux of 8.4 103 Wb passes through it. The same net magnetic flux passes through the second surface. (a) Determine the area of the first surface. (b) Find the smallest possible value for the area of the second surface.

take note that the question has not specified th angle which the surface is tilted so i assume the angle is at 12^{0} to the horizontal

flux = BAcos(\alpha)

B=magnetic flux in Weber

A=area of the flat surface in m^2

\alpha=the angle to the horizontal

a) 8.4 x10^-3= (.47)Acos(78)

alpha has to be the angle from the normal and not the horizontal so 90-12=78,

 8.4 x10^-3

/(.47)cos(78)

A = 0.0859 m^2

b) If flux remains the same then for it to be the smallest possible area it needs to be perpendicular to the magnetic field so alpha would be 0.

8.4 x10^-3 = (.47)Acos(0)

A = 0.0178 m^2

7 0
4 years ago
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