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Y_Kistochka [10]
4 years ago
11

Newton's law of universal gravitation works well in ordinary situations on earth, but it does not work well

Physics
2 answers:
IRINA_888 [86]4 years ago
6 0

Answer:

For large masses,It does not work well

Explanation:

Newton's law of universal gravitation :

  In the universe every particle attract the other particle by a force and this force is directly proportional to product of their masses and inversely proportional to distance between these two masses.This law given as follows

F=G\dfrac{m_1m_2}{r^2}

Where G is the constant.

Th one limitation of this law that the masses should not be too large.So this law does not work well for large bodies.

USPshnik [31]4 years ago
3 0
In large stars because they are too massive
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Answer:

The force on q₁ due to q₂ is (0.00973i + 0.02798j) N

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F₂₁ = \frac{K|q_1|q_2|}{r^2}.\frac{r_2_1}{|r_2_1|}

Where;

F₂₁ is the vector force on q₁ due to q₂

K is the coulomb's constant = 8.99 X 10⁹ Nm²/C²

r₂₁ is the unit vector

|r₂₁| is the magnitude of the unit vector

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r₂₁ = [(9-5)i +(7.4-(-4))j] = (4i + 11.5j)

|r₂₁| = \sqrt{(4^2)+(11.5^2)} = \sqrt{148.25}

(|r₂₁|)² = 148.25

F_2_1=\frac{K|q_1|q_2|}{r^2}.\frac{r_2_1}{|r_2_1|} = \frac{8.99X10^9(14X10^{-6})(60X10^{-6})}{148.25}.\frac{(4i + 11.5j)}{\sqrt{148.25} }

      = 0.050938(0.19107i + 0.54933j) N

      = (0.00973i + 0.02798j) N

Therefore, the force on q₁ due to q₂ is (0.00973i + 0.02798j) N

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