"Acceleration" does NOT mean "speeding up".
"Acceleration" means ANY change in the speed or direction of motion.
An object can speed up, slow down, or turn a corner.
Each of these is an example of acceleration.
3.19 x 10^8... hope this helps.
Answer:
I guess the answer was d.The current at P is greater than the current at Q...
Answer: option b.
Explanation:
The kinetic energy of a spring with constant K is calculated as:
kinetic energy = (k/2)*x^2
Where x^2 is the displacement of the spring with respect to it's rest position.
This can be written as a function like:
x = A*cos(2*pi*f*t)
where:
A is the amplitude (the maximum distance that the spring can move in each direction)
f is the frequency (and 2*pi*f is the angular frequency)
and t is the variable, it represents the time.
Replacing this in the kinetic energy equation, we get:
kinetic energy = (k/2)*(A*cos(2*pi*f*t))^2
This is the same as the option b: b. 1/2kA^2cos^2(2πft)
Then the corrrect option is b.
Answer:
P_2 = 62.69 psi
Explanation:
given,
P₁ = 70 psia T₁ = 55° F = (55 + 459.67) R
P₂ = ? T₂ = 115° F = (115 + 459.67) R
we know,
p = ρ RT
ρ is the density which is constant
R is also constant
now,
![\dfrac{P_2}{P_1} =\dfrac{T_2}{T_1}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_2%7D%7BP_1%7D%20%3D%5Cdfrac%7BT_2%7D%7BT_1%7D)
![\dfrac{P_2}{70} =\dfrac{55+459.67}{115+459.67}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_2%7D%7B70%7D%20%3D%5Cdfrac%7B55%2B459.67%7D%7B115%2B459.67%7D)
P_2 = 62.69 psi
Hence, the increase in Pressure is equal to P_2 = 62.69 psi