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3 years ago

Given the system of linear equations

Mathematics

1 answer:

kvasek [131]3 years ago

6 0

Use the slope-intercept form to find the slope and y-intercept.
Slope:
3
3
y-intercept:
(
0
,
2
)

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What is the solution to this system of equations?

maksim [4K]

Answer:x=3 y=1/2

Step-by-step explanation:

x+2y=4

2x-2y=5

Add both equations together

x+2x+2y-2y=4+5

3x+0=9

3x=9

Divide both sides by 3

3x/3=9/3

x=3

Substitute x=3 in x+2y=4

x+2y=4

3+2y=4

Collect like terms

2y=4-3

2y=1

Divide both sides by 2

2y/2=1/2

y=1/2

8 0

2 years ago

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0

2 years ago

120% of what number is 48

postnew [5]

Answer:

120 percent (calculated percentage %) of what number equals 48? Answer: 40.

8 0

3 years ago

What is the domain and range and function ??? Then can u explain how u did it please and thank you

enot [183]

The domain is
$- 10 \leqslant x \leqslant 10$
and the range is
$- 5 \leqslant y \leqslant 5$
Domain is x values (horizontal axis), while range is y values (vertical axis). On a line like this one, domain is calculated from the left most point to the right most, while range is calculated from the down most to the upmost.
Because this line is a solid line rather than a dotted line, less than or equal to
$\leqslant$
signs are used rather than just
$<$
less than signs.

6 0

3 years ago

Construct a quadratic equation whose roots are -2\3 and 5

Vladimir79 [104]

_Brainliest if helped!

Roots -2/3 and 5 Means X=-2/3 or X=5
Hence the equation would be
(X+2/3)(X-5)=0
(3X+2)(X-5)=0
$3X^{2} +2X -15X -10 = 0 
$
Answer : $3X^{2} -13X-10=0$

4 0

3 years ago