r₁ = distance of the point from the source = 43 km = 43000 m
I₁ = intensity of earthquake wave at distance "r₁" = 2.5 x 10⁶ W/m²
r₂ = distance of the point from the source = 1.5 km = 1500 m
I₂ = intensity of earthquake wave at distance "r₂" = ?
we know that , for a constant power , the intensity of wave is inversely proportional to the distance from the source .
I α 1/r² where I = intensity of wave , r = distance from source
hence we can write
I₁/I₂ = r₂²/r₁²
inserting the values
(2.5 x 10⁶) /I₂ = (1500/43000)²
I₂ = 2.1 x 10⁹ W/m²
Answer:
The heat capacity of the sample of metal is 664j/kg.°C
Explanation:
Kindly find attached a detailed solution to this question for you reference.
Given data
Mass of sample m1= 0.45kg
Temperature of sample θs= 80°c
Mass of water mw = 0.7kg
Temperature of water θw= 15°C
Specific heat capacity of water Cw=
4200j/kg.°C
Equilibrium Temperature θ3= 21°C
HEAT LOSS BY SUBSTANCE =HEAT GAINED BY WATER
What is Quantity of heat?
Quantity of heat is the amount of heat absorbed or given out by a body Q=mcθ
What is the heat capacity?
Heat capacity is the amount of heat required to raise the temperature of a substance by 1k.The S.I unit is joule per Kelvin J/k
What is specific heat capacity?
The specific heat capacity is the amount of heat required to raise the temperature of 1kg of substance by 1k
Answer:
Velocity will be equal to 7.31 m/sec
Explanation:
We have given mass of the student m = 61 kg
Height of the water slide h = 12.3 m
Acceleration due to gravity
Potential energy is equal to
Work done due to friction = -5800 J
So energy remained = 7352.94-5800 = 1552.94 J
This energy will be equal to kinetic energy
So
v = 7.13 m/sec
Velocity = distance / time
velocity = 3.5m/8.9s
your velocity = 0.39 m/s (1)
Answer:
The greater the rotation angle in a given amount of time, the greater the angular velocity. Angular velocity ω is analogous to linear velocity v. We can write the relationship between linear velocity and angular velocity in two different ways: