A. Through the direct contact of particles
25 x 10^-5
= 0.00025
25 cm
= 0.00025 km
Here we apply conservation of linear momentum. The momentum of the truck with cargo and without cargo remains constant. That is,
.
Here
are initial mass and velocity.
are final mass and velocity. Here
and
.
The velocity of the truck be after its cargo is taken off is

Answer:
a) v = 19,149.6 m/s
b) f = 95%
c) t = 346.5min
Explanation:
First put all values in metric units:

The equation of motion you need is:
where
is the final velocity, a is acceleration and t is time in hours.
Since the spaceship starts from 0 velocity:

Next, you need to calculate the distances traveled on each interval, considering that both starting and final intervals travel the same distance because the acceleration and time are equal. For this part you need the next motion equation:

solving for first and last interval:
Since the spaceship starts and finish with 0 velocity:

Then the ship traveled
at constant speed, which means that it traveled:

Which in percentage is 95% of the trip.
to calculate total time you need to calculate the time used during constant speed:

That added to the other interval times:

I'll put my answer in the comments but, part of the question is cut off do you mind putting a more readable and not sideways picture?