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kotykmax [81]
3 years ago
9

The figure above shows 4forces 3N, 10N, 3√3N, and 6N acting on a particle P. The resultant of the four forces is.

Physics
1 answer:
Brilliant_brown [7]3 years ago
6 0

As you gave no pic I took them on one lined

  • F_1=3N
  • F_2=10N
  • F_3=3root 3 N
  • F_4=6N

\\ \sf\longmapsto F_{net}=F_1+F_2\dots

\\ \sf\longmapsto F_{net}=3+10+6+3\sqrt{3}

\\ \sf\longmapsto F_{net}=19+3(1.732)

\\ \sf\longmapsto F_{net}=19+5.196

\\ \sf\longmapsto F_{net}=24.196N

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3 years ago
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3 years ago
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3 years ago
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Aleksandr-060686 [28]

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Hope this helps! Have a fantastic rest of ur day, luv!

8 0
3 years ago
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fiasKO [112]
Let's use the mirror equation to solve the problem:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i}
where f is the focal length of the mirror, d_o the distance of the object from the mirror, and d_i the distance of the image from the mirror.
For a concave mirror, for the sign convention f is considered to be positive. So we can solve the equation for d_i by using the numbers given in the text of the problem:
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6 0
3 years ago
Read 2 more answers
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