All categories

3 years ago

What is the Lewis dot diagram structure for PI2F

Chemistry

1 answer:

Brut [27]3 years ago

3 0

Answer:

Please find attached the completed Lewis dot diagram structure for PI₂F

Explanation:

The number of valence electrons are;

Phosphorus = 5 Electrons

Iodine = 2 × 7 electrons = 14 electrons

Chlorine = 7 electrons

The total number of valence electrons = 14 + 7 + 5 = 26 electrons

2) We draw the symbol that represents the basic (general) structure of the molecule as follows;

The sheared electron pair are represented by single bond lines

3) We complete the octet structures round the fluorine and the iodine atoms as attached showing 18 electrons plus 6 shared electron pairs, with a maximum from step 2 to give a total of (18 + 6) 24 electron pairs

4) We add the 2 unaccounted valence electron on the phosphorus atom to give it the stable octet structure, which gives the completed Lewis structure

You might be interested in

A solution contains 3.1 mM Zn(NO3)2 and 4.2 mM Ca(NO3)2. The p-function for Zn2+ is _____, and the p-function for NO3- is _____.

seropon [69]

Answer: The p-function of $Zn^{2+}$ and $NO_3^{-}$ ions are 2.51 and 2.14 respectively.

Explanation:

p-function is defined as the negative logarithm of any concentration.

We are given:

Millimolar concentration of zinc nitrate = 3.1 mM

Millimolar concentration of calcium nitrate = 4.2 mM

Converting this into molar concentration, we use the conversion factor:

1 M = 1000 mM

Concentration of zinc nitrate = 0.0031 M = 0.0031 mol/L

1 mole of zinc nitrate produces 1 mole of zinc ions and 2 moles of nitrate ions

Concentration of zinc ions = 0.0031 M

Concentration of nitrate ions in zinc nitrate, $M_1=(2\times 0.0031)=0.0062M$

Concentration of calcium nitrate = 0.0042 M = 0.0042 mol/L

1 mole of calcium nitrate produces 1 mole of calcium ions and 2 moles of nitrate ions

Concentration of calcium ions = 0.0042 M

Concentration of nitrate ions in calcium nitrate, $M_2=(2\times 0.0042)=0.0084M$

To calculate the concentration of nitrate ions in the solution, we use the equation:

$M=\frac{M_1V_1+M_2V_2}{V_1+V_2}$

Putting values in above equation, we get:

$M=\frac{(0.0062\times 1)+(0.0084\times 1)}{1+1}\\\\M=0.0073M$

Calculating the p-function of zinc ions and nitrate ions in the solution:

For zinc ions:

$\text{p-function of }Zn^{2+}\text{ ions}=-\log[Zn^{2+}]$

$\text{p-function of }Zn^{2+}\text{ ions}=-\log(0.0031)\\\\\text{p-function of }Zn^{2+}\text{ ions}=2.51$

For nitrate ions:

$\text{p-function of }NO_3^{-}\text{ ions}=-\log[NO_3^{-}]$

$\text{p-function of }NO_3^{-}\text{ ions}=-\log(0.0073)\\\\\text{p-function of }NO_3^{-}\text{ ions}=2.14$

Hence, the p-function of $Zn^{2+}$ and $NO_3^{-}$ ions are 2.51 and 2.14 respectively.

5 0

3 years ago

Why do some substances react with each other while others do not

kolbaska11 [484]

It depends on the Chemical the Substance has. The more Chemicals, the better the Substance gets when its mixed with another.

7 0

3 years ago

Which statement below is the BEST explanation for the differences

IgorC [24]

Answer:

Explanation:

Electron geometry describes the arrangement of electron groups. Molecular geometry describes the arrangement of atoms, excluding lone pairs.

7 0

3 years ago

"calculate the ratio of the velocity of hydrogen molecules to the velocity of carbon dioxide molecules at the same temperature"

Ne4ueva [31]

Answer: 1:4.69

Explanation:

The ratio can be expressed as:

Ua/Ub= √(Mb/Ma)

Where Ua/Ub is the ratio of velocity of hydrogen to carbon dioxide and Ma is the molecular mass of hydrogen gas= 2

Mb is the molecular mass of CO2 = 44

Therefore

Ua/Ub= √(44/2)

Ua/Ub = 4.69

Therefore the ratio of velocity of hydrogen gas to carbon dioxide = 1:4.69

which implies hydogen is about 4.69 times faster than carbon dioxide.

8 0

3 years ago

Astronomers often scan the sky using devices called radio

sukhopar [10]

Answer:

A radio telescope is simply a telescope that is designed to receive radio waves from space.

radio telescopes helps to study naturally occurring radio light from stars, galaxies, black holes, and other astronomical objects. We can also use them to transmit and reflect radio light off of planetary bodies in our solar system.

6 0

2 years ago

Read 2 more answers