Question

Find the indicated values, where g(t)=t^2-t and f(x)=1+x g(f(2)+3)

Answer 1

Answer:

$g(f(2)+3)=30$

Step-by-step explanation:

We have the two functions:

$g(t)=t^2-t\text{ and } f(x)=1+x$

And we wish to find:

$g(f(2)+3)$

First, let’s find f(2) first. So, we will substitute 2 for x for f(x):

$f(2)=1+(2)=3$

Hence, we can now substitute 3 for f(2):

$g(f(2)+3)=g(3+3)=g(6)$

Now, we can find g(6). Substitute 6 for t for g(t):

$g(6)=(6)^2-(6)=36-6=30$

Therefore:

$g(f(2)+3)=30$