2 sqrt3 + 3 sqrt3
= 5 sqrt3
Since this contains the irrational sqrt3 it is irrational
We are given area of the ribbon = 144 square inches.
We know formula for side of a square =
.
Plugging value of area in the formula, we get
Side of the square 
= 12 inches.
Sonya wants to sew ribbon along each side of a square pillow.
So, we need to find the perimeter of the square pillow.
<h3>Perimeter = 4 × side = 4 × 12 = 48 inches.</h3><h3>Therefore, she buy 48 inches of ribbon to have the exact amount that she needs.</h3>
Answer:
L=1 ft and B=84 ft
L=2 ft and B=42 ft
L=4ft and B=21ft
L=6ft and B=14 ft
L=7ft and B=12ft
L=12 ft and B=7ft
L=14ft and B=6 ft
L=21 ft and B=4 ft
L=42 ft and B=2 ft
L=84 ft and B=1 ft
Step-by-step explanation:
We are given that
Area of rectangular floor=84 square feet
We have to find the possible length and width of for Angelo's clubhouse.
Area of rectangle=
Using the formula
Area of rectangular floor for clubhouse=84 square feet

Factor of 84 are
1,2,4,6,7,12,14,21,42,84
Therefore, possible dimension of rectangular floor

L=1 ft and B=84 ft
L=2 ft and B=42 ft
L=4ft and B=21ft
L=6ft and B=14 ft
L=7ft and B=12ft
L=12 ft and B=7ft
L=14ft and B=6 ft
L=21 ft and B=4 ft
L=42 ft and B=2 ft
L=84 ft and B=1 ft
Answer:
b)4 11/10
Step-by-step explanation:
Answer:
Given
length of rectangular sheet of paper is 12 (1/2) i.e. (25/2)
Breadth of rectangular sheet of paper is 10 (2/3) i.e. (32/3)
But we know that perimeter of rectangle = 2 (length + breadth)
Perimeter of rectangular sheet = 2 [(25/2) + (32/3)]
LCM of 2 and 3 is 6,
by taking this and simplifying we get
Perimeter = 2[(25 × 3)/6 + (32 × 2)/6]
= 2[(75/6) + (64/6)]
= 2(139/6) = (139/3)
= 46 (1/3) cm