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Lady_Fox [76]
2 years ago
9

If an engineer's greatest concern is specific impulse, which type of fuel should she use?

Chemistry
1 answer:
alexandr402 [8]2 years ago
8 0

Answer: D. (Liquid fuel)

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Draw the main lewis structure of nof. draw nonbonding electrons using the dot notation and bonding electrons as a bond.
navik [9.2K]

solution is attached below

6 0
3 years ago
Read 2 more answers
Silver nitrate reacts with aluminum chloride to form the insoluble compound, silver chloride. The reaction proceeds according to
viva [34]

The theoretical yield of silver chloride, AgCl is 5.2109 g

The balanced equation for the reaction is given below:

<h3>3AgNO₃(aq) + AICI₃(aq) —> Al(NO₃)₃ (aq) + 3AgCl (s) </h3>

Next, we shall determine the mass of aluminum chloride, AICI₃ that reacted and the mass of silver chloride, AgCl produced from the balanced equation. This is illustrated below:

Molar mass of AICI₃ = 133.34 g/mol

Mass of AICI₃ from the balanced equation = 1 × 133.34 = 133.34 g

Molar mass of AgCl = 143.32 g/mol

Mass of AgCl from the balanced equation = 3 × 143.32 = <em>429.96 g</em>

<h3>SUMMARY</h3>

From the balanced equation above,

133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.

Finally, we shall determine the theoretical yield of AgCl by the reaction of 1.616 g of AICI₃ as follow:

From the balanced equation above,

133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.

Therefore,

1.616 g of AICI₃ will react to produce = \frac{1.616 * 429.96}{133.34} = 5.2109 g of AgCl.

Thus, the theoretical yield of silver chloride, AgCl is 5.2109 g

Learn more: brainly.com/question/24653699

3 0
3 years ago
What is the empirical formula of a compound containing 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen?
Anvisha [2.4K]

Answer:

= C3H4N

Explanation:

We are given; 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen.

We first calculate the number of moles of each element.

Carbon = 90g/12 g/mol

            = 7.5 moles

Hydrogen = 11 g/ 1 g/mol

                 = 11 moles

Nitrogen = 35 g/ 14 g/mol

               = 2.5 moles

The we get the mole ratio of the elements;

= 7.5/2.5 : 11/2.5 : 2.5 /2.5

= 3 : 4.4 : 1

= 3 : 4 : 1

Therefore;

The empirical formula will be; C3H4N

6 0
3 years ago
1. How many moles of NaCl would be contained in .750 L solution with a molarity of<br> 0.45M?
Evgesh-ka [11]
Formula of Molarity =

Molarity = no. of moles /volume of solution in L

Given, 0.45M= no. of moles/0.750L
Therefore, no. of moles = 0.45M x 0.750L= 0.3375
5 0
2 years ago
Read 2 more answers
When vectors are added or subtracted, the net force is called the _____.
Bezzdna [24]

Answer:

resultant

Explanation:

4 0
2 years ago
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