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Lady_Fox [76]
2 years ago
9

If an engineer's greatest concern is specific impulse, which type of fuel should she use?

Chemistry
1 answer:
alexandr402 [8]2 years ago
8 0

Answer: D. (Liquid fuel)

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Question: Describe how a river changes the earth´s surface. please explain in your own words, might be reported if answer is c o
11111nata11111 [884]

Answer:

Answer down below

Explanation:

Through the processes of erosion and deposition, rivers and streams can drastically alter the Earth's surface. ... The rushing water of rivers helps to carve new features into the surface of the Earth.

3 0
2 years ago
Read 2 more answers
In the periodic table hydrogen is placed in Group 1A (group 1) and helium is placed in Group 8A (group 18). The most likely reas
Alexus [3.1K]

Answer:

This question appears incomplete

Explanation:

This question appears incomplete because of the absence of options. However, hydrogen is placed in group 1 because it has just one electron in it's outermost shell (which happens to be the only shell it has) just like every other group 1A/group 1 element. While helium is placed in group 8A/group 18 because it has a completely filled outermost shell (which is also the only shell it has) just like every other element in group 8A/group 18.

8 0
3 years ago
Why are bubbles and precipitates both signs of chemical change
BartSMP [9]

Answer:(I didn’t really know where to Wrigh-)

Explanation: Gas bubbles appear after a chemical reaction has occurred and the mixture becomes saturated with gas. The chemical change that creates the gas is completed after the gas bubbles leave the mixture.

8 0
2 years ago
How many moles of Fe are in 235.45g of Fe
Elena-2011 [213]
We are given with an element Iron, Fe, with a mass of 235.45 g. We are tasked to solve for its corresponding molar mass in mol. We need to find first the molecular weight of Iron, that is
Fe= 55.845 g/mol
With 235.45 g sample, its corresponding mol is

mol Fe= 235.45 g x 1 mol/55.845 = 4.22 mol Fe
Therefore, molar mass of Iron is 4.22 mol
3 0
3 years ago
What volume of 0.235 M H2SO4 is needed to titrate 40.0 mL of 0.0500 M Na2CO M NaCO3 solution?
Andreyy89

Answer: The volume of 0.235 M H_2SO_4 needed to titrate 40.0 mL of 0.0500 M Na_2CO_3 is 8.51 ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Na_2CO_3

We are given:

n_1=2\\M_1=0.235M\\V_1=?mL\\n_2=2\\M_2=0.0500M\\V_2=40.0mL

Putting values in above equation, we get:

2\times 0.235\times V_1=2\times 0.0500\times 40.0\\\\V_1=8.51mL

Thus volume of 0.235 M H_2SO_4 needed to titrate 40.0 mL of 0.0500 M Na_2CO_3 is 8.51 ml

5 0
3 years ago
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