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Lady_Fox [76]
3 years ago
9

If an engineer's greatest concern is specific impulse, which type of fuel should she use?

Chemistry
1 answer:
alexandr402 [8]3 years ago
8 0

Answer: D. (Liquid fuel)

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How many moles of cf4 are there in 171g of cf4 ?
xeze [42]
1 is + 4  = to n please
5 0
3 years ago
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Use the given data at 500 K to calculate ΔG°for the reaction
Anton [14]

Answer : The  value of \Delta G^o for the reaction is -959.1 kJ

Explanation :

The given balanced chemical reaction is,

2H_2S(g)+3O_2(g)\rightarrow 2H_2O(g)+2SO_2(g)

First we have to calculate the enthalpy of reaction (\Delta H^o).

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{H_2O}\times \Delta H_f^0_{(H_2O)}+n_{SO_2}\times \Delta H_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta H_f^0_{(H_2S)}+n_{O_2}\times \Delta H_f^0_{(O_2)}]

where,

\Delta H^o = enthalpy of reaction = ?

n = number of moles

\Delta H_f^0 = standard enthalpy of formation

Now put all the given values in this expression, we get:

\Delta H^o=[2mole\times (-242kJ/mol)+2mole\times (-296.8kJ/mol)}]-[2mole\times (-21kJ/mol)+3mole\times (0kJ/mol)]

\Delta H^o=-1035.6kJ=-1035600J

conversion used : (1 kJ = 1000 J)

Now we have to calculate the entropy of reaction (\Delta S^o).

\Delta S^o=S_f_{product}-S_f_{reactant}

\Delta S^o=[n_{H_2O}\times \Delta S_f^0_{(H_2O)}+n_{SO_2}\times \Delta S_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta S_f^0_{(H_2S)}+n_{O_2}\times \Delta S_f^0_{(O_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S_f^0 = standard entropy of formation

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (189J/K.mol)+2mole\times (248J/K.mol)}]-[2mole\times (206J/K.mol)+3mole\times (205J/K.mol)]

\Delta S^o=-153J/K

Now we have to calculate the Gibbs free energy of reaction (\Delta G^o).

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

At room temperature, the temperature is 500 K.

\Delta G^o=(-1035600J)-(500K\times -153J/K)

\Delta G^o=-959100J=-959.1kJ

Therefore, the value of \Delta G^o for the reaction is -959.1 kJ

3 0
3 years ago
Which contains more molecules; a mole of Chlorine gas (Cl2 ) or a mole of glucose (C6H1206) ?
Elodia [21]
This is a tricky question. a mole of any compound contains the same number of molecules of that certain compound. so, one mole of chlorine gas has the same number of molecules as one mole of glucose, which is 6.02 x 10^23.

this is avogadro's number and it applies for any mole of molecules. 

the question is tricky because it is like asking. " what weighs more, a pound of feathers or a pound of rocks?" the both weigh the same, a pound. when ewe talking about moles, same as pounds, it is a quantity unit. one mole will aways be equal to 6.02 x 10^23 molecules.
7 0
3 years ago
These are all chemistry questions please help
SpyIntel [72]

Answer:

cant read the questions...

Explanation:

4 0
3 years ago
Why is a crystal of Strontium chloride described as an extended structure?
olchik [2.2K]

Answer:

Explanation:

Chloride is described as an extended structure because its atoms are arranged following an endless repeating pattern and are of distinct ratio

Crystals and polymers mostly form extended structures as seen in the formation of sodium chloride whereby the ions in the compound are arranged following a repeating pattern. ( i.e. has a giant ionic structure ).

Chloride is a considered an extended structure because in sodium chloride it forms an unending repeated pattern of ions which makes it a perfect example of an extended structure.

Hence we can conclude that Chloride can be described as an extended structure because its atoms are arranged following a repeating pattern and are of distinct ratio.

5 0
2 years ago
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