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Lapatulllka [165]
2 years ago
9

What is the expected charge on an ion of nitrogen? A. -3 B. +3 C. +8 D. +5

Chemistry
1 answer:
Firlakuza [10]2 years ago
8 0
A. -3


hhhhhjhhhhhhhhhtghhhhhh (this is just bc the answer has to be at least 20 characters long don't mind this)
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Explain why there would be an environmental problem if sulfur dioxide gas escaped into the atmosphere
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When sulfur dioxide combines with water and air, it forms sulfuric acid, which is the main component of acid rain. Acid rain can: cause deforestation. acidify waterways to the detriment of aquatic life

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3 years ago
Objects 1 and 2 collide and stick together. Which best describes the momentum of the resulting single object? It is less than th
Mariulka [41]

Answer:

The answer would be D

Explanation:

Hope I helped <3

5 0
3 years ago
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Calculate the pH of 0.50M H2S
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I got that pH=3.65 using the fact that Ka=[H⁺][A⁻]/[HA] at equilibrium.  In the ice table, I stands for initial, C stands for change, and E stands for equilibrium.  

I hope this helps.  Let me know if anything is unclear.

5 0
2 years ago
For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.43×10-4 /s and the
ladessa [460]

<span>Answer is: activation energy of this reaction is 212,01975 kJ/mol.
Arrhenius equation: ln(k</span>₁/k₂) = Ea/R (1/T₂ - 1/T₁<span>).
k</span>₁<span> = 0,000643 1/s.
k</span>₂ = 0,00828 1/s.

T₁ = 622 K.

T₂ = 666 K.

R = 8,3145 J/Kmol.

1/T₁<span> = 1/622 K = 0,0016 1/K.
1/T</span>₂<span> = 1/666 K = 0,0015 1/K.
ln(0,000643/0,00828) = Ea/8,3145 J/Kmol · (-0,0001 1/K).
-2,55 = Ea/8,3145 J/Kmol · (-0,0001 1/K).
Ea = 212019,75 J/mol = 212,01975 kJ/mol.</span>

4 0
3 years ago
The average speed of oxygen molecules in air is about ____. (1 point) 0 km/h 170 km/h 1700 km/h 17,000 km/h
LenKa [72]

The average speed is calculated using the following formulaspeed = \sqrt{\frac{3kT}{m} }


Where

k = 1.381 X  10^{-23} J / K

T = 298 K [room temperature]

m = mass of each molecule of oxygen

mass of one mole of oxygen molecules = 32 g / mol

mass of one molecule of oxygen will be = \frac{32}{6.023 X 10^{23} }

mass of one molecule of oxygen will be = 5.31 X 10^{-23} g = 5.31 X 10^{-26} kg

putting values

average speed = \sqrt{\frac{3 X 1.381 X  10^{-23} X 298}{5.31 X 10^{-26} kg} }

Average speed = 482.19 m / s

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so approx = 1700 km/h

4 0
3 years ago
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