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ElenaW [278]
3 years ago
13

Based on your knowledge of energy conservation, which of the following statements is true?

Chemistry
1 answer:
Julli [10]3 years ago
3 0
C. both a and b

If a light bulb can last longer with the same amount of energy it is given, that means it can use less energy to do the same job compared to one that does not last longer with the same amount of energy it is given. It is much like how a more fuel efficient car will be able to go farther on the same tank of gas, but if you pair it with a car that doesn't have as great of an mpg, when they go the same distance, the car with the greater mpg spends less fuel.

If you don't have to use the energy when you aren't utilizing it, then you can conserve the energy for when you do need it.
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Lithium, sodium and potassium are all in group 1 of the periodic table. Which of these has the lowest boiling point?
kvv77 [185]

Answer:

Potassium

Explanation:

In group one of the periodic table both the melting and the boiling points usually decrease down the group.

Now, down the group, it's lithium that comes first, then sodium, then potassium.

Thus, among the 3, potassium is furthermost down the group by virtue of the factor it has the highest atomic number.

Therefore, we can say that potassium has the lowest boiling point among the 3.

5 0
2 years ago
Name four ways that bacteria are helpful to people
vesna_86 [32]
<span>gives you dairy products 
helps fight disease 
helps digest food 
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8 0
3 years ago
Balance this equation K+b2o3=k2o+b
AVprozaik [17]

Answer:

Explanation:

2K and 2b

5 0
3 years ago
A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL of 2.00 M KOH in a calorimeter. The temperature of both sol
Reika [66]

Answer : The enthalpy change for the process is 52.5 kJ/mole.

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the solution

q=[q_1+q_2]

q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]

where,

q = heat released by the reaction

q_1 = heat absorbed by the calorimeter

q_2 = heat absorbed by the solution

c_1 = specific heat of calorimeter = 12.1J/^oC

c_2 = specific heat of water = 4.18J/g^oC

m_2 = mass of water or solution = Density\times Volume=1/mL\times 100.0mL=100.0g

\Delta T = change in temperature = T_2-T_1=(26.3-20.2)^oC=6.1^oC

Now put all the given values in the above formula, we get:

q=[(12.1J/^oC\times 6.1^oC)+(100.0g\times 4.18J/g^oC\times 6.1^oC)]

q=2623.61J

Now we have to calculate the enthalpy change for the process.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat released = 2626.61 J

n = number of moles of copper sulfate used = Concentration\times Volume=1M\times 0.050L=0.050mole

\Delta H=\frac{2623.61J}{0.050mole}=52472.2J/mole=52.5kJ/mole

Therefore, the enthalpy change for the process is 52.5 kJ/mole.

8 0
3 years ago
Outline two methods used by designers to assemble packages​
Lostsunrise [7]

Answer:

Product packaging design refers to the production of a product's exterior. Develop an organization. All these specifics allow one to consider what the sealed substance is about how to use it, who can use it, and maybe, What do you sell? For your product, there are several different packaging forms available.

Explanation:

8 0
2 years ago
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