Well, technically it would have a pH reading and or measurement of 0. As a ph of 1 would represent that there are hydrogen ions, no matter how less present in the solution, since pH is a measure of Hydrogen ions present in a solution, a pH value of 0 would mean virtually no protons, hydrogen ions.
Answer:
17. HC₂H₃O₂ + H₂O ⇄ C₂H₃O₂⁻ + H₃O⁺ Ka
A B CB CA
18. H₂SO₄ + 2H₂O → 2H₃O⁺ + SO₄⁻²
A B CA CB
19. CO₃⁻² + H₂O ⇄ HCO₃⁻ + OH⁻ Kb
B A AC BC
20. HCO₃⁻ + NH₃ ⇄ CO₃⁻² + NH₄⁺ Ka
A B BC AC
21. NH₄⁺ + OH⁻ ⇄ NH₃ + H₂O Ka
A B BC AC
Explanation:
The acetic acid release a proton to water, to produce acetate and hydronium.
This is a weak acid.
The sulfuric acid release 2 protons to water to produce sulfate and hydronium.
This acid is considered as strong, but it is only strong in the first dissociation. The second dissociation is weak, with a Ka.
Carbonate takes a proton from water, to become bicarbonate (In this case, the carbonate behaves as a base).
Bicarbonate release a proton to ammonia, to make ammonium and carbonate anion.
Amonium cation release a proton to the hydroxide to make ammonia and water.
Answer:
The answer to your question is Synthesis and Endothermic
Explanation:
Balanced chemical reaction
H₂ + F₂ ⇒ 2HF + 546 kJ
Chemical reactions can be classified in different ways, so I suggest two names of this reaction.
1.- This is a synthesis reaction because two different reactants form a new compound.
2.- This is an endothermic reaction because it was needed to supply 546 kJ of energy so that the reaction proceeds.
Explanation:
Copper sulphate reacts with potassium iodide to form cuprous iodide and iodine.
2CuSO
4
+4KI→Cu
2
I
2
↓+I
2
+2K
2
SO
4
Thus, CuI
2
is not formed in this reaction.
Hence, the option B is incorrect and option A is correct.
The liberated iodine is titrated with sodium thiosulphate to form sodium tetrathionate.
2Na
2
S
2
O
3
+I
2
→Na
2
S
4
O
6
+2NaI
Iodine is reduced and sodium thiosulphate is oxidized.
Chemical change, because the atoms are being rearranged and we get a new substance.