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bearhunter [10]
2 years ago
8

HELP PLEASE!!!!

Chemistry
2 answers:
Elena-2011 [213]2 years ago
4 0

Answer:

This is not accurate we dont know what your asking us?

Explanation:

Marysya12 [62]2 years ago
4 0

Answer:

i need help to on this one 2

Explanation:

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How many moles of SnF₂ will be produced along with 48 grams of H₂? *
KIM [24]

Answer: 24 moles of SnF_2 are produced.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

{\text{Moles of}  H_2}=\frac{48g}{2g/mol}=24moles

Sn+2HF\rightarrow SnF_2+H_2

According to stoichiometry :

1 mole of H_2 is accompanied with = 1 mole of SnF_2

Thus 24 moles of H_2  is accompanied with =\frac{1}{1}\times 24=24moles  of SnF_2

Thus 24 moles of SnF_2 are produced.

8 0
3 years ago
Calculate the change in energy when 75.0 grams of water drops from<br> 31.0C to 21.6.
zysi [14]

Answer: Step 1: Calculate qsur (the surrounding is

usually the water)

qsur = ? J

m = 75.0 g water

c = 4.184 J/g

oC

ΔT = (Tfinal- Tinitial)= (21.6 – 31.0) = -9.4 oC

qsur = m · c · (ΔT)

qsur = (75.0g) (4.184 J/g

oC) (-9.4 oC)

qsur = - 2949.72 J

First, using the information we know that we

must solve for qsur, which is the water. We know

the mass for water, 75.0g, the specific heat of

the water, 4.184 j/g

o

c, and the change in

temperature, 21.6-31.0 = -9.4 oC. Plugging it

into the equation, we solve for qsur.

Step 2: Calculate qsys qsys = - (qsur)

qsys = - (- 2949.72 J)

qsys = + 2949.72

In this case, the qsur is negative, which means

that the water lost energy. Where did it go? It

went to the system. Thus, the energy of the

system is negative, opposite, the energy of the

surrounding.

Step 3: Calculate moles of the substance

that is the system

Given: 12.8 g KCl

Mol system = (g system given)

(molar mass of system)

Mol system = (12.8 g KCl)

(39.10g + 35.45g)

Mol system = 12.8 g KCl

74.55 g

Mol system = 0.172

Here, we solve for the mol in the system by

using the molar mass of the material in the

system.

Step 4: Calculate ΔH ΔH = q sys .

Mol system

ΔH= + 2949.72 J

0.172 mol

ΔH= +17179.81 J/mol or +1.72 x 104

J/mol

i hope this helps

5 0
3 years ago
Read 2 more answers
Balance it by oxidation number method:Zn +HNO3----Zn(NO3)2+NO+H2O​
timofeeve [1]

Answer:

Answer:

step 1:balance skeleton equation the chemical equation:

Zn +HNO3➔Zn(NO3)2+NO+H2O

step 2: identity undergoing oxidation or reduction

here

Zn➔Zn(NO3)2

Zn is oxidized from 0 to 2 in oxidation no.

HNO3➔NO

N is reduced from 5 to 2 in oxidation no

Step 3: calculate change in oxidation no.

change in oxidation no

in Zn=0-2=-2=2

in

N=5-2=3

Step 4: Balance it by doing crisscrossed multiplication

we get;

3Zn +2HNO3➔3Zn(NO3)2+2NO+H2O

step 6:Balance other atoms except H & O

3Zn +2HNO3➔3Zn(NO3)2+2NO+H2O

3Zn +2HNO3+6HNO3➔3Zn(NO3)2+2NO+H2O

finally: balance H

<em><u>3Zn +8HNO3➔3Zn(NO3)2+2NO+4H2O</u></em>

3 0
3 years ago
Read 2 more answers
Write the molecular formula in the of the following compounds.
tensa zangetsu [6.8K]
Calcium bicarbonate - Ca(HCO3)2
sodium peroxide - Na202
water - H20
silver nitrate - AgN03
potassium carbonate - K2CO3
sodium carbonate - Na2CO3
zinc chloride - ZnC12
calcium hydroxide - Ca(OH)2
magnesium chloride - MgC12
4 0
3 years ago
Q #13 How many moles of MgCl2 are there in 350. g of compound?
Vaselesa [24]

<u>Answer:</u>

3.67 moles

<u>Step-by-step explanation:</u>

We need to find out the number of MgCl_2 moles present in 350 grams of a compound.

Molar mass of Mg = 24.305

Molar mass of Cl_2 = 35.453

So, one mole of MgCl_2 = 24.305 + (35.453 * 2) = 95.211g

1 Mole in 1 molecule of MgCl_2 = \frac{1}{95.211} = 0.0105

Therefore, number of moles in 350 grams of compound = 0.0105 * 350

= 3.67 moles



8 0
3 years ago
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