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Andru [333]
3 years ago
12

When a car climbs a hill, it has only potential energy True or false ​

Physics
2 answers:
Dmitriy789 [7]3 years ago
7 0

Answer:

On the way back up the hill, the car converts kinetic energy to potential energy. In the absence of friction, the car should end up at the same height as it started. ... The total energy of the ball stays the same but is continuously exchanged between kinetic and potential forms.

Explanation:

hope it helps :D

xenn [34]3 years ago
6 0

As the car gets higher and higher on the hill, it collects more and more potential energy.

But if it's moving, then it also has kinetic energy.

So the statement is False.

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Answer:

The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q.

Explanation:

Electric field strength is a vector quantity; it has both magnitude and direction. The magnitude of the electric field strength is defined in terms of how it is measured. Let's suppose that an electric charge can be denoted by the symbol Q. This electric charge creates an electric field; since Q is the source of the electric field, we will refer to it as the source charge. The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q. When placed within the electric field, the test charge will experience an electric force - either attractive or repulsive. As is usually the case, this force will be denoted by the symbol F. The magnitude of the electric field is simply defined as the force per charge on the test charge.

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4 years ago
John, paul, and george are standing in a strawberry field. paul is 14.0 m due west of john. george is 36.0 m from paul, in a dir
sdas [7]

Position of paul with respect to john is given as

14 m due west of john

r_{pj} = r_p - r_j = -14\hat i

position of George with respect to Paul is given as 36 m in direction 37 degree south of east

r_{GP} = r_G - r_p = 36cos37\hat i - 36 sin37\hat j

now we need to find the position of George with respect to John

r_{GJ} = r_G - r_j[\tex]now for the above equation we can add the two equations[tex]r_{Gj} = -14\hat i + 36 cos37\hat i - 36sin37\hat j

r_{Gj} = 14.75\hat i - 21.67\hat j

so the magnitude is given as

r = \sqrt{14.75^2 + 21.67^2} = 26.2 m

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3 years ago
Read 2 more answers
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