Explanation:
we know that,
linear speed = circumference × revolution per minute
linear speed of belt = 2πr × revolution per minute
now we will compute the linear speed of a belt for 2 inch pulley that is,
linear speed for 2 inch pulley = (2π×2)×( 3 revolutions per minute) ∵ r =2
= 4π × 3 revolution per minute (1)
again we will compute the linear speed of a belt for 8 inch pulley,
linear speed of 8 inch pulley = (2π×8) × (x revolution per minute) ∵ r =8
= 16π×x revolutions per minute (2)
As the linear speed is same for both pulleys. by comparing equations (1) and (2).
4π×3 = 16π×x
x = 3/4
Thus, the revolutions per minute for the 8 inch pulley is 3/4.
Work is force times distance. So here we have
W=(5000N)x(3000m)=1.5x10^7J
Or 15MJ (megajoules)
Well, you haven't given us much of a choice of graphs to pick from, have you.
If a sample of an ideal gas is held at constant temperature, then
its pressure and volume are inversely proportional ... the harder
you squeeze it, the smaller the volume gets, and less squeeze
produces more volume.
Actually, the product of (pressure) x (volume) is always the
same number.
The graph of that relationship is all in the first quadrant.
It starts out very high right next to the y-axis, then drops down
toward the x-axis while curving to the right and becoming horizontal,
and ends up trying to get closer and closer to the x-axis but never
actually becoming zero.
The net force on q2 will be 1.35 N
A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.
Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.
We have to find the net force on q2
At first we will find Force due to q1
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²
F = 450 × 10⁻³
F₁ = 0.45 N (+)
Now we will find Force due to q2
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²
F = 1800 × 10⁻³
F₂ = 1.8 N (-)
So net force (F) will be
F = F₂ - F₁
F = 1.8 - 0.45
F = 1.35 N
Hence the net force on q2 will be 1.35 N
Learn more about force here:
brainly.com/question/25573309
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Answer:
The two Russian authors based their exposition on what they called the Friedmann theory of a singular beginning of the universe, referring throughout to the “theory of the hot universe” as an alternative to the hot Big Bang theory.
