A rock is stuck deep in the dirt. When you pull on the rock to remove it, what type of force are you exerting?
2 answers:
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The initial velocity of car 1 is 20 m/s to the right
The initial velocity of car 2 is zero
The final velocity of car 2 is 10 m/s to the right
Explanation:
We can solve the problem by using the law of conservation of momentum: the total momentum of the system must be conserved before and after the collision.
Therefore, we can write:
where:
is the mass of the first car
is the initial velocity of the first car
is the final velocity of the first car (taking right as positive direction)
is the mass of the second car
is the initial velocity of the second car
is the final velocity of the second car
We also know the initial momentum of car 1, which is
And since momentum is the mass times the velocity, we find the initial velocity of car 1:
with a positive sign, since the direction is to the right.
Now we can re-arrange the previous equation and solve for v2, the final velocity of car 2:
And since the sign is positive, the direction is the same as the initial direction of car 1, so to the right.
Learn more about momentum here:
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Answer:
The distance up to which they can jump is 1.5 m
Solution:
As per the question:
The extension of the legs, d = 0.600 m
Acceleration,
where
g = acceleration due to gravity =
Now,
Let the initial velocity of the jump be v m/s
So, by the third eqn of motion:
(1)
where
v' = final velocity
a = acceleration
d = distance between the legs
Also, for maximum range, angle,
(2)
x = maximum horizontal range
Thus, using eqn (1):
Now, using eqn (2):