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4 years ago

15

You draw 1 card at random from a well-shuffled deck of 52 cards, put it back, reshuffle, and draw another card at random. The ev

ents "get the queen of hearts on the first draw" and "get the ace of spades on the second draw" are independent events.
True or False

1 answer:

wolverine [178]4 years ago

3 0

This answer would be true. I believe. It would be that because they are completely separate.

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Help please someone please

mote1985 [20]

1728292882292.7282728

5 0

3 years ago

Enter the ratio as a fraction in lowest terms<br><br> 6 ft to 40 in.

tresset_1 [31]

Answer:

9 in. to 5 in.

or 9/5

Step-by-step explanation:

6 ft=6*12=72 in.

6 ft/ 40 in.=72/40=9/5

9 in. to 5 in.

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4 years ago

Read 2 more answers

PLEASE HELP ASAP, DUE IN AN HR!!!

rusak2 [61]

Answer:

$\dfrac38 \text{ sq in}$

Step-by-step explanation:

plug 1/4 into the formula for surface area and simplify to get 6/16, or 3/8.

7 0

3 years ago

Read 2 more answers

Solve : <br>4² ( 4³ )<br>with work shown

stepan [7]

Answer:

1024

Step-by-step explanation:

4²(4³)

4×4(4×4×4)

16(16×4)

16(64)

16×64

=1024

7 0

3 years ago

A cylinder has a helght of 16 cm and a radius of 5 cm. A cone has a helght of 12 cm and a radius of 4 cm. If the cone is placed

erma4kov [3.2K]

Answer:

1055.04 cm³

Step-by-step explanation:

Given that,

Height of a cylinder, h = 16 cm

Radius of the cylinder, r = 5 cm

The height of a cone, h' = 12 cm

The radius of a cone, r' = 4 cm

The volume of the cylinder will be :

$V=\pi r^2 h\\\\=3.14\times 5^2\times 16\\\\=1256\ cm^3$

The volume of a cone is given by :

$V'=\dfrac{1}{3}\pi r^2 h\\\\=\dfrac{1}{3}\times 3.14\times (4)^2\times 12\\\\=200.96\ cm^3$

Volume of the air surrounding the cone Inside the cylinder = 1256 - 200.96 = 1055.04 cm³

Hence, the required answer is equal to 1055.04 cm³.

3 0

3 years ago