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const2013 [10]
3 years ago
9

If a star contains a certain element, it can be determined by studying the star’s

Physics
1 answer:
valentina_108 [34]3 years ago
3 0
A. Emission spectrum
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Which of the following correctly describes the importance of demonstrations to scientific investigation?
sergey [27]

Answer:

A- A demonstration shows how something works, often including models

Explanation:

A demonstration allows, through experimentation, to show how nature works and in that way can include the explanation of scientific theories that explain the set of observed facts, that is, it serves as a demonstration of the underlying scientific principles.

5 0
3 years ago
A steel ball and a piece of clay have equal mass. They are dropped from the same height on a horizontal steel platform. The ball
emmasim [6.3K]

Answer: The ball (option A)

Explanation: change in momentum is defined by the formulae m(v - u) where m = mass of object, v = final velocity and u = initial velocity.

For the ball, it hits the ground and bounces back with the same speed, that's final velocity equals initials (v = - u)

Change in momentum = m( -u- u) = m(-2u) = m(-2u) = -2mu

For the clay, it final velocity is zero since it sticks to the floor, hence (v =0)

m(v - u) = m(0 - u) = - mu.

-2mu (change in momentum from the ball) is greater than - mu ( change in momentum of clay)

6 0
3 years ago
A certain AM radio wave has a frequency of 1.12 x 100 Hz. Given that radio waves travel at
riadik2000 [5.3K]

Answer: 267 m

Explanation:

2.99x10^8 m/s

———————-

1.12 x 10^6 Hz

3 0
2 years ago
Which of the following statements is true for a cell placed in beaker containing an isotonic solution?
Korvikt [17]
An isotonic solution is <span>a solution in which concentration or solute is equal to that of a cell placed in it. Thus, the system is in dynamic equilibrium, and so water molecules flow in both directions.
The correct answer is <u>C. w</u></span><span><u>ater molecules flow in both directions at the same rate.</u></span>
3 0
3 years ago
On August 10, 1972, a large meteorite skipped across the atmosphere above the western United States and western Canada, much lik
Anon25 [30]

a) 4.62\cdot 10^{14} J

b) 0.110 megatons

c) 8.46 bombs

Explanation:

a)

The energy lost by the meteorite is equal to the difference between its final kinetic energy and its initial kinetic energy:

\Delta K=K_f-K_i

Which can be rewritten as:

\Delta K=\frac{1}{2}mv^2-\frac{1}{2}mu^2

where:

m=3.2\cdot 10^6 kg is the mass of the meteorite

v=0 is the final speed of the meteorite

u=17 km/s = 17,000 m/s is the initial speed of the meteorite

Substituting the values into the equation, we found the loss in energy of the meteorite:

\Delta K=0-\frac{1}{2}(3.2\cdot 10^6)(17000)^2=-4.62\cdot 10^{14} J

So, the energy lost by the meteorite is 4.62\cdot 10^{14} J

b)

The energy equivalent to 1 megaton of TNT is

E_{TNT}=4.2\cdot 10^{15} J

Here the energy lost by the meteorite is

E=4.62\cdot 10^{14} J

Therefore, in order to write the energy lost by the meteorite as a multiple of the energy of 1 megaton of TNT, we have to divide the energy lost by the meteorite by the energy equivalent to 1 TNT; we find:

\frac{E}{E_{TNT}}=\frac{4.62\cdot 10^{14}}{4.2\cdot 10^{15}}=0.110

So, the energy lost by the meteorite corresponds to 0.110 megatons.

c)

The energy of one atomic bomb explosion in Hiroshima is equal to

E'=13 kt (13 kilotons)

which corresponds to

E'=0.013 Mt (0.013 megatons)

Here the energy of the meteorite is equal to

E=0.110 Mt (0.110 megatons)

Therefore, we can find how many Hiroshima bombs are equivalent to teh meteorite impact by using the following rules of three:

\frac{1 bomb}{0.013 Mt}=\frac{x bombs}{0.110 Mt}\\x=\frac{1\cdot 0.110}{0.013}=8.46

So, 8.46 bombs.

5 0
2 years ago
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