Answer:
Ф_cube /Ф_sphere = 3 /π
Explanation:
The electrical flow is
Ф = E A
where E is the electric field and A is the surface area
Let's shut down the electric field with Gauss's law
Фi = ∫ E .dA = 
/ ε₀
the Gaussian surface is a sphere so its area is
A = 4 π r²
the charge inside is
q_{int} = Q
we substitute
E 4π r² = Q /ε₀
E = 1 / 4πε₀ Q / r²
To calculate the flow on the two surfaces
* Sphere
Ф = E A
Ф = 1 / 4πε₀ Q / r² (4π r²)
Ф_sphere = Q /ε₀
* Cube
Let's find the side value of the cube inscribed inside the sphere.
In this case the radius of the sphere is half the diagonal of the cube
r = d / 2
We look for the diagonal with the Pythagorean theorem
d² = L² + L² = 2 L²
d = √2 L
we substitute
r = √2 / 2 L
r = L / √2
L = √2 r
now we can calculate the area of the cube that has 6 faces
A = 6 L²
A = 6 (√2 r)²
A = 12 r²
the flow is
Ф = E A
Ф = 1 / 4πε₀ Q/r² (12r²)
Ф_cubo = 3 /πε₀ Q
the relationship of these two flows is
Ф_cube /Ф_sphere = 3 /π
Answer:
Explanation:
In order to calculate the equivalent spring constant we need to use the next formula:
Replacing the data provided:
Finally, to calculate the frequency of oscillation we use this:
Replacing m and k:
Because you see yourself the opposite way in a mirror. So yes your “seeing” yourself but not how everyone else sees you.
Answer:
D. Half as great
Explanation:
Since we know that the friction force between the surface of crate and ground is given as
so here we know that
= friction coefficient between two surfaces which depends on the effective contact area between two surfaces
= normal force due to the object
So when we turn the object on another side such that the surface area is half then the friction coefficient will become also half
So here the friction force will also reduce to half
so correct answer will be
D. Half as great
Answer:
size of popcorn seed may meet the scaled earth size of x = 0.07312 in.
Explanation:
Given:-
- The diameter of actual sun, Ds = 1.3927 * 10^6 km
- The diameter of model sun ball, ds = 8 in
- The diameter of the actual earth, De = 12,742 km
Find:-
How large would be the earth model
Solution:-
- We can use the actual diameters of the earth and sun to develop the ratio of earth diameter to that of sun. The direct ratio can be used to model the diameter of earth for the scale model
Sun Earth
Actual : 1392700 km 12,742 km
Scale : 8 in x
- Use direct relations and solve for x:
x = (8 in)*(12,742 km ) / ( 1392700 km )
x = 0.07312 in.
- From the given options apple, grapefruit and marble diameters are larger than 1 inch. So only the size of popcorn seed may meet the scaled earth size of x = 0.07312 in.
