Answer:
Using the log combination rules to reduce the famous Sakur-Tetrode equation, The change in entropy is given as:
∆S = NK*ln(V"V$/V").
Where V"V$ is final Volume (Vf) after constraint's removal,
V" is Initial Volume (Vi) before constraint's removal.
Temperature (T) is constant, Internal Energy, U is constant, N and K have their usual notations
Explanation:
Given in the question, the container is an adiabatic container.
For an adiabatic contain, it does not permit heat to the environment due to its stiff walls. This implies that the Internal Energy, U is kept constant(Q = U). The temperature is also constant (Isothermal). Thus, the famous Sakur-Tetrode equation will reduce to ∆S = NK* In(Vf/Vi).
Vf is the volume after the constraint is removed(Vf = V"V$). Vi is the volume occupied before the constraint is removed (Vi = V")
Answer:
a) One-ninth the force acting on object A.
Explanation:
First, we derive an expression for the centripetal force acting on both objects.
For object A, centripetal force is:
For object B, centripetal force is:
We are given that they have the same mass and they move in circles of the same radius.
If object A completes three times as many rotations as object B, then, object must have 3 times the speed of object B.
Hence:
Therefore, 
becomes:
=> 
Therefore, the net centripetal force acting on object B is one-ninth of the force acting on object A.
Answer:
The value is 
Explanation:
From the question we are told that
The wavelength is 
The distance of separation is 
The distance from the screen is 
Generally the separation between the adjacent bright fringe is mathematically represented as
=> 
=>
<span>To do this question, we need to know that momentum is conserved, meaning the overall velocity of the two balls has to be the same before and after the collision. </span>
<span>After collision... </span>
<span>Ball 1: 4.33m/s *cos 30 = 3.75 m/s (x-component) </span>
<span>4.33m/s * sin 30 = 2.165 m/s ( y-component) </span>
<span>Ball 2 (struck ball): 5 m/s - 3.75m/s = 1.25 m/s (x-component) </span>
<span>-2.165 m/s (y-component) note: it has to be in the opposite direction to conserve momentum </span>
<span>tan-1(2.165/1.25) = 60 degrees </span>
<span>Struck ball's velocity = sqrt(1.25^2 + 2.165^2) = 2.5 m/s at 60 degree with respect to the original line of motion. </span>
<span>Hope you understand!</span>
The electron cloud is split up in 3 areas.
1) Inner Electron Cloud
2) Outer Electron Cloud
3) Valence Electrons
Your inner cloud is the electrons CLOSEST to the nucleus.
Your outer cloud is the electrons in the MIDDLE of the Inner and Valence.
Your valence electrons are the OUTER LAYER of electrons. These electrons are important to bonding, and also are what decide where on the periodic table of elements. For example:
197
Au
79
This element is GOLD. It has 1 valence, therefor it is where it is in the period. Ionization could change this number however.
