Answer:
Products
Explanation:
In an endothermic reaction, energy is taken in. This means that the absorption of energy favours the forward reaction.
Hence for a process; A + B----> C, if energy must be added for the equilibrium to shift towards the right and more of C is produced, then the reaction is endothermic.
Answer:
<h3>
Which of the following increases with the increase in the temperature in case of a liquid?</h3><h2>
<em>Va</em><em>pour</em><em> </em><em> </em><em>Pressure</em><em> </em></h2>
Explanation:
When a closed container contains liquid, higher the temperature, higher the evaporation the evaporation will be.
So Vapour Pressure should be the correct answer.
Plasma has similar physical characteristics to gas, in that it flows freely and drifts and separates to fill the container it's in. Plasma occurs at super high temperatures, this strips apart the molecules. It can also occur at relatively cool temperatures, this plasma has very charged particles. They are electrically neutral, as they often contain equal numbers of protons and neutrons. But they are still affected by electric and magnetic fields, because they are so free flowing.
Answer:
Explanation:
We must use the Nernst equation
The equation for the cell reaction is is
2Cl⁻(0.384 mol·L⁻¹) + 2Co³⁺(0.324 mol·L⁻¹) ⇌ Cl₂(5.80 atm) + 2Co²⁺(0.158 mol/L)
Data:
E° = 0.483 V
R = 8.314 J·K⁻¹mol⁻¹
T = 25 °C
n = 2
F = 96 485 C/mol
Calculation:
T = 25 + 273.15 = 298.15 K
![Q = \dfrac{\text{[Cl}^{-}]^{2}[\text{Co}^{3+}]^{2}}{p_{\text{Cl}_{2}}^{2}\text{[Co}^{3+}]^{2}} = \dfrac{0.384^{2} \times 0.324^{2}}{5.80 \times 0.158^{2}} =0.1069\\\\E = 0.483 - \left (\dfrac{8.314 \times 298.15 }{2 \times 96485}\right ) \ln(0.1069)\\\\=0.483 -0.01285 \times (-2.236) = 0.483 + 0.02872 = \textbf{0.512 V}\\\text{The cell potential is } \large\boxed{\textbf{0.512 V}}](https://tex.z-dn.net/?f=Q%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BCl%7D%5E%7B-%7D%5D%5E%7B2%7D%5B%5Ctext%7BCo%7D%5E%7B3%2B%7D%5D%5E%7B2%7D%7D%7Bp_%7B%5Ctext%7BCl%7D_%7B2%7D%7D%5E%7B2%7D%5Ctext%7B%5BCo%7D%5E%7B3%2B%7D%5D%5E%7B2%7D%7D%20%3D%20%5Cdfrac%7B0.384%5E%7B2%7D%20%5Ctimes%200.324%5E%7B2%7D%7D%7B5.80%20%5Ctimes%200.158%5E%7B2%7D%7D%20%3D0.1069%5C%5C%5C%5CE%20%3D%200.483%20-%20%5Cleft%20%28%5Cdfrac%7B8.314%20%5Ctimes%20298.15%20%7D%7B2%20%5Ctimes%2096485%7D%5Cright%20%29%20%5Cln%280.1069%29%5C%5C%5C%5C%3D0.483%20-0.01285%20%5Ctimes%20%28-2.236%29%20%3D%200.483%20%2B%200.02872%20%3D%20%5Ctextbf%7B0.512%20V%7D%5C%5C%5Ctext%7BThe%20cell%20potential%20is%20%7D%20%5Clarge%5Cboxed%7B%5Ctextbf%7B0.512%20V%7D%7D)
