Answer: Scientific notation- ![1.51 x 10^{-1}](https://tex.z-dn.net/?f=1.51%20x%2010%5E%7B-1%7D)
Explanation: I got this by moving the decimal, so that there is one non-zero digit to the left of that decimal point. Tip- The number of decimal places you move will be the exponent on the 10.
Moved right- Negative
Moved left- Positive
The balanced equation that shows the reaction between oxalic acid and permanganate ion in an acidic medium is: 2MnO4- + 5H2C2O4 + 6H+ -> 2Mn(2+) + 10CO2 + 8H2O. Thus, 1 mole of oxalic acid reacts with 0.4 mole of permanganate ion. This was obtained using stoichiometry:
1 mol H2C2O4 x (2 mol MnO4-/ 5 mol H2C2O4) = 0.4 mol MnO4-
In this redox reaction, the permanganate is reduced to manganese(II) ion.
Answer:
The diagr displays the "DIFFUSION" of oxygen from the red blood cells into the capillary to the body cells
Solution :
A cell that is concentrated is constructed by the same half reaction for the anode as well as he cathode.
We know,
In a standard cell,
the reduction half cell reaction is :
![$Ag^+(aq)+e^- \rightarrow Ag(s) E^0 = -0.80 \ V$](https://tex.z-dn.net/?f=%24Ag%5E%2B%28aq%29%2Be%5E-%20%5Crightarrow%20Ag%28s%29%20E%5E0%20%3D%20-0.80%20%5C%20V%24)
The oxidation half ell reaction :
![$Ag(s) \rightarrow Ag^+(aq) + e^- \ E^0= +0.80 \ V$](https://tex.z-dn.net/?f=%24Ag%28s%29%20%5Crightarrow%20Ag%5E%2B%28aq%29%20%2B%20e%5E-%20%5C%20E%5E0%3D%20%2B0.80%20%5C%20V%24)
Thus the complete reaction of the cell is :
![$Ag^+(aq)+ Ag(s) \rightarrow Ag^+(aq)+Ag(s)$](https://tex.z-dn.net/?f=%24Ag%5E%2B%28aq%29%2B%20Ag%28s%29%20%5Crightarrow%20Ag%5E%2B%28aq%29%2BAg%28s%29%24)
cell = ![$E_R - E_L = 0.00 \ \text{volts}$](https://tex.z-dn.net/?f=%24E_R%20-%20E_L%20%3D%200.00%20%20%5C%20%5Ctext%7Bvolts%7D%24)
Protons and neutrons. Electrons are on the outside layers. Protons are the ones with a positive charge and neutrons have a neutral charge. Electrons have a negative charge. Hope this helps :)