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3 years ago

The shirts cost a $150 for a 100 shirts how much per shirt

Mathematics

1 answer:

Rufina [12.5K]3 years ago

5 0

Answer:

$1.5 per shirt if that's what you meant

Step-by-step explanation:

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De que numero es 552 el 8%menos

djyliett [7]

8% of 552 is 44.16. Look at the percent sign as a decimal and move it two places to the left, that'll give you 0.08. To find 8% of 552, look at it as 0.08 multiplied by 552. After you multiply you should get 44.16.

8 0

3 years ago

What is 2+2? <br><br> Wrong answers only

Fittoniya [83]

Answer:

Step-by-step explanation:

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3 years ago

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Ryann planned on swimming 14 miles. Instead, he was only able to swim 1/4 of that distance. How many miles did Ryan swim?

mote1985 [20]

Hey there,

Given the question it shows that Ryann swam 1/4 of 14 miles that he was supposed to swim.

In words of is another way to say 1/4 * 14...

14/4

This expressed as a mixed number would be...

3 and 2/4 or 3 1/2

Of the 14 miles that Ryann was supposed to swim he swam 3 1/2 miles.

Hope I helped,

Amna

8 0

3 years ago

Read 2 more answers

LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6

USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

The coordinates are given as:

$\mathbf{(x,y) = (-60,0)\ (60,0)}$

The center of the hyperbola is

$\mathbf{(h,k) = (0,0)}$

The distance from the center to the focal points is given as:

$\mathbf{c = 60}$

Square both sides

$\mathbf{c^2 = 3600}$

The distance from the receiver to the transmitters is given as:

$\mathbf{2a = 100}$

Divide both sides by 2

$\mathbf{a = 50}$

Square both sides

$\mathbf{a^2 = 2500}$

We have:

$\mathbf{b^2 = c^2 - a^2}$

This gives

$\mathbf{b^2 = 3600 - 2500}$

$\mathbf{b^2 = 1100}$

The equation of an hyperbola is:

$\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}$

So, we have:

$\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}$

$\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

Hence, the equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$