An airplane is flying in a horizontal circle at a speed of 92.1 m/s. The 55.6 kg pilot does not want his radial acceleration to
exceed 8.45 g. The acceleration of gravity is 9.8 m/s². What is the minimum radius of the circular path?
1 answer:
Answer:
r = 102.43 m
Explanation:
Newton's second law for this case is
F = ma
Where the acceleration is centripetal
a = v² / r
r = v² / a
They indicate that the radial acceleration is 8.45 g
r = v² / 8.45 g.
r = 92.1² / 8.45 9.8
r = 102.43 m
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