Answer:
20.1 m/s
Explanation:
Since You are later than usual getting to the stop and see the shuttle pulling away from the stop while you are still 3.9 m behind the bus stop. And In 40.9 m you will reach a barrier and you must catch the shuttle before that point.
Given that the shuttle has a constant acceleration of 4.5 m/s2.
The total distance to cover is:
Total distance = 40.9 + 3.9 = 44.8 m
Assuming you are starting from rest. Then initial velocity U = 0
Using the 3rd equation of motion to calculate the minimum velocity.
V^2 = U^2 + 2as
V^2 = 0 + 2 × 4.5 × 44.8
V^2 = 403.2
V = sqrt (403.2)
V = 20.1 m/s
Therefore, the minimum velocity you have to run at to catch the bus before it reaches the barrier is 20.1 m/s
This phenomenon can be describedby Hooke'slaw and expressed by the formula: F=k*deltax, where k is the spring's constant, and delta xis the displacement of the spring. Transposing the terms such that we want to know the value of k,
k = F/deltax = 100N/(22 cm - 20cm)
k = 50 N/cm
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Answer: 3.33 m/s
Explanation:
Assuming the questions is to convert 12 km/h to meter per second (m/s), let's begin:
In order to make the conversion, we have to know the following:
And:
Keeping this in mind, we can make the conversion:
Then:
Answer:
can I have a picture or like options
Explanation:
please , if you send them I'll edit answer
