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slega [8]
3 years ago
11

About 10% of the water in the world ocean makes up all of the surface currents. most surface currents move water above the _____

__________, the zone of maximum density change per unit depth.
Physics
1 answer:
pogonyaev3 years ago
3 0
The answer to this is Pycnocline.
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Bad White [126]
The answer is b maybe?
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3 years ago
HELPPPPPPPP PLSSSSSSSS A car moves with constant velocity along a straight road. Its position is x1 = 0 m at t1 = 0 s and is x2
yawa3891 [41]

Answer:

Explanation:

6.2 miles

6 0
3 years ago
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In 2.8 s, a car increases its velocity from 20. M/s to 25 m/s. What is the acceleration of the car
Akimi4 [234]
Acceleration= change in velocity/time; 5/2.8 , so a=1.785714286
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3 years ago
Answer all of these questions and you will get the brainlist
Rina8888 [55]
7) PE= Fwh = (72 m) (966 N) = 69552 Joules 7
8) zero PE=mass*g*height
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6 0
3 years ago
A spaceship ferrying workers to Moon Base I takes a straight-line path from the earth to the moon, a distance of 384,000 km. Sup
Tema [17]

Answer:

a) v = 19,149.6 m/s

b) f = 95%

c) t = 346.5min

Explanation:

First put all values in metric units:

15.8 min*\frac{60s}{1min}=948s

The equation of motion you need is:

v_f = a*t+v_0

where v_f is the final velocity, a is acceleration and t is time in hours.

Since the spaceship starts from 0 velocity:

v_f = a*t = 20.2*948 = 19,149.6 m/s

Next, you need to calculate the distances traveled on each interval, considering that both starting and final intervals travel the same distance because the acceleration and time are equal. For this part you need the next motion equation:

x=\frac{v_0+v_f}{2}t

solving for first and last interval:

Since the spaceship starts and finish with 0 velocity:

x=\frac{v}{2}t=\frac{19,149.6}{2}948=9,076,910.4m=9,076.9104km

Then the ship traveled 384,000-9,076.9104*2 = 361,846.1792km at constant speed, which means that it traveled:

f_{constant_speed} =\frac{ x_{constant_speed}}{x_total} =\frac{361,846.1792}{380,000} =0.95

Which in percentage is 95% of the trip.

to calculate total time you need to calculate the time used during constant speed:

t = \frac{361,846,179.2}{19,149.6} = 18,895.75s = 314min

That added to the other interval times:

t_{total} = t_1+t_2+t_3=15.8+314.93+15.8=346.5min

5 0
3 years ago
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