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xz_007 [3.2K]
3 years ago
15

Find the mistake Astudent calculated their answer to a gas law problem as shown in the image below. Their answer is incorrect. R

eview the work
and find them the student made their calculation. The question is typed in the upper left corner there is only 1 step that is incorrect
Chemistry
1 answer:
Darina [25.2K]3 years ago
5 0
Gavaiavauyuwti you are doing ok well I have to go get some stuff and stuff for the shop and then I can help out the work stuff for my dad and stuff so I’m not going to work today or do I whave to u
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Que cambios son fisicos y cuales son quimicos??
melomori [17]
<span>A, b, y c son cambios físicos. D es un cambio químico.</span>
6 0
3 years ago
What is the answer with the correct significant figures to the addition problem 1.2773 + 4.29
vladimir2022 [97]

Answer:5.5673

Explanation: I searched it up for you

5 0
3 years ago
Which of the following is not the same as 0.032 liters?<br> a)32 mL<br> b)0.00032 hL<br> c)320 cL
Charra [1.4K]
C) why because it’s says 320 cL wich means that.....
6 0
3 years ago
In the reaction, 2 Al (s) + 6HCL (aq) --&gt; 2ALCL3 (aq) + 3 H2 (g), 2.00 g of Al will react with how many milliliters of 0.500
san4es73 [151]

Answer:

The volume of HCl required is V = 420 mL

Explanation:

From the question we are told that

    The chemical equation for this reaction is

             2 Al _{(s)} + 6 HCl _{(aq)} -----> 2 Al Cl_{3} _{(aq)} + 3 H_2 _{(g)}

    The mass of Al  is m__{Al}} = 2.00g

    The concentration of HCl is C__{HCl}} = 0.500M

The number of moles of Al given is n__{Al}} = \frac{mass \ of  Al}{Molar \ mass \ of \ Al}

   The molar mass of Al is  M = 27 g/mol

       So

               n__{Al} = \frac{2}{27}

               n__{Al} =  \ 0.07 \ moles

From the balanced equation

           2 moles of  Al  reacts  with  6 moles of  HCl

So        0.07 moles of Al will react with x

  Therefore

                x = \frac{0.07 *6}{2}

                x = 0.21 \ moles

Now the volume of HCl can be obtained as

           Volume(V) = \frac{moles}{concentration }

 So       V = \frac{0.21}{0.500}

             V = 420 mL

8 0
3 years ago
Cobalt, Co, has 27 electrons. Write out the entire electron configuration for cobalt using spdf notation.
Hatshy [7]

Answer:

Co = 1s2 2s2 2p6 3s2 3p6 4s2 3d7

Explanation:

Number of electrons = 27

The closest noble gas before cobalt is Argon and argon has 18 electrons.

Co = [Ar]  ; Remains 27 - 18 = 9  more electrons to fill.

The next orbital in order of increasing energy is the 4s orbital. However it can only hold a maximum of 2 electrons.

We have;

Co = [Ar] 4s2; Remains 27 - 20 = 7 more electrons to fill.

The next orbital in order of increasing energy is the 3d orbital. It can have a maximum of 10 electrons.

So we have;

Co = [Ar] 4s2 3d7

The electronic configuration of Ar = 1s2 2s2 2p6 3s2 3p6

This means the entire configuration of cobalt is;

Co = 1s2 2s2 2p6 3s2 3p6 4s2 3d7

8 0
3 years ago
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