how many grams of oxygen are produced if 25.0g of potassium chlorate decomposes according to the reaction 2KCLO3 —-> 2KCL +3O
2 answers:
Answer:
9.79g of O2
Explanation:
So this question you are trying to go from g of KCLO3 to grams of oxygen. There is no direct conversion so you have to utilize multiple process.
=9.79 g of O2
So first you go from g of KCLO3 to moles of KCLO3 by using molar mass of KCLO3. Then you use mol:mol ratio from balanced equation to go to moles of O2, and finally use molar mass of O2 to go to grams of O2.
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Answer:
63.52°C is the final temperature
Explanation:
1) 131.0 mL of water at 26.0°C
Mass of water = m
Volume of the water =131.0 mL
Density of the water = 1.00 g/mL
m = 131.0 g
Initial temperature of the water = = 26.0°C
Final temperature of the water =
Change in temperature ,
Heat absorbed 131.0 g of water = Q
2) 81.0 mL of water at 85.0°C
Mass of water = m'
Volume of the water =81.0 mL
Density of the water = 1.00 g/mL
m' = 81.0 g
Initial temperature of the water = = 85.0°C
Final temperature of the water =
Change in temperature ,
Heat lost by 81.0 g of water = Q'
After mixing both liquids the final temperature will become equal fro both liquids.
Since, heat lost by the water at higher temperature will be equal to heat absorbed by the water at lower temperature.
Q=-Q' (Law of conservation of energy.)
Let the specific heat of water be c
63.52°C is the final temperature