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Aleksandr [31]
3 years ago
8

Assertion (A): An orbital cannot have more than two electrons, moreover, if an orbital has two electrons they must have opposite

spins.
Reason (R): No two electrons in an atom can have the same set of all the four quantum
numbers.
a) Both A and R are true and R is the correct explanation of A.
b) Both A and R are true but R is not the correct explanation of A.
c) A is true but R is false.
d) Both A and R are false.
pls answer
Chemistry
2 answers:
VMariaS [17]3 years ago
7 0

Answer: Its option "A" Both A and R are true and R is the correct explanation of A.

Hope it helps

storchak [24]3 years ago
6 0

Answer:

the correct answer is option ( A )

Both A and R are true and R is the correct explanation of A.

Explanation:

hope it helps you

Mark my answer as brainlist

have a nice day

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Hydrogen bonds form between molecules containing _________ bonds; the hydrogen bond is between a hydrogen atom of one molecule a
nasty-shy [4]

Answer:

The answer is A. Polar covalent; negatively

Explanation:

Hydrogen bonds form between molecules containing polar covalent bond the hydrogen bond is been a hydrogen atom of one molecule and a partially negative charged atom of another.

Example H_{2}O (water):- It contain a slight positive charge on one side and a slight negative charge on the other.

5 0
3 years ago
What is an atom that has the same number of protons as other atoms of the same element, but has a different number of neutrons?
PSYCHO15rus [73]

Answer:

isotopes

Atoms with the same number of protons but different numbers of neutrons are called isotopes. Because the number of neutrons can vary for a given element, the mass numbers of different atoms of an element may also vary. For example, some helium atoms have three neutrons instead of two (these are called isotopes and are discussed in detail later on)

Explanation:

4 0
3 years ago
What is the concentration of x2??? in a 0.150 m solution of the diprotic acid h2x? for h2x, ka1=4.5??10???6 and ka2=1.2??10???11
lutik1710 [3]
The first dissociation for H2X:
                        H2X +H2O ↔ HX + H3O
initial                0.15                     0      0
change             -X                     +X      +X
at equlibrium 0.15-X                  X        X
because Ka1 is small we can assume neglect x in H2X concentration
     Ka1      = [HX][H3O]/[H2X]
4.5x10^-6 =( X )(X) / (0.15)
X = √(4.5x10^-6*0.15) 
∴X = 8.2 x 10-4 m
∴[HX] & [H3O] = 8.2x10^-4
the second dissociation of H2X
        HX + H2O↔ X^2 + H3O
    8.2x10^-4          Y         8.2x10^-4
Ka2 for Hx = 1.2x10^-11
Ka2       = [X2][H3O]/[HX]
1.2x10^-11= y (8.2x10^-4)*(8.2x10^-4)
∴y = 1.78x10^-5
∴[X^2] = 1.78x10^-5 m


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