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Aleksandr [31]
3 years ago
8

Assertion (A): An orbital cannot have more than two electrons, moreover, if an orbital has two electrons they must have opposite

spins.
Reason (R): No two electrons in an atom can have the same set of all the four quantum
numbers.
a) Both A and R are true and R is the correct explanation of A.
b) Both A and R are true but R is not the correct explanation of A.
c) A is true but R is false.
d) Both A and R are false.
pls answer
Chemistry
2 answers:
VMariaS [17]3 years ago
7 0

Answer: Its option "A" Both A and R are true and R is the correct explanation of A.

Hope it helps

storchak [24]3 years ago
6 0

Answer:

the correct answer is option ( A )

Both A and R are true and R is the correct explanation of A.

Explanation:

hope it helps you

Mark my answer as brainlist

have a nice day

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A compound is 21.6% Mg, 21.4% C, and 57.0% O. What is the empirical formula of the compound? ​
nignag [31]

Answer:

Compound x = MgC_{2}O_{4}

Explanation:

Let the compound be x

Assuming we have a 100g of compound x

<u>Given the following data;</u>

Magnesium, Mg = 21.6% = 21.6g

Carbon, C = 21.4% = 21.4g

Oxygen, O = 57.0% = 57.0g

Now, we would find the amount of moles for each element.

Atomic mass of Mg = 24.30g

Atomic mass of C = 12.01g

Atomic mass of O = 16.00g

<u>Amount of moles for Mg;</u>

21.6*(1/24.30) = 0.89mol

<u>Amount of moles for C;</u>

21.4*(1/12.01) = 1.78mol

<u>Amount of moles for O;</u>

57.0*(1/16.00) = 3.56mol

We then divide by the smallest to find the ratio;

0.89/0.89 = 1 Mol of Mg

1.78/0.89 = 2 Mol of C

3.56/0.89 = 4 Mol of O

Therefore, the ratio of Mg, C and O is 1:2:4.

Compound x = MgC_{2}O_{4}

Hence, the empirical formula of the compound is MgC_{2}O_{4}

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