Answer:
The answer for (a)(-5.96, 2.36) (b) -1.8, since the difference is negative, it can be said or determined that the age of the grandfather is older
Step-by-step explanation:
Solution
(a) From the information given,
n = 10, d =-1.8, sd = 5.81
The 95% confidence interval for the population mean difference age is computed as follows:
CI =d ±tα/2,n-1 (sd/√n)
= -1.8±t₀.₀₅/₂,₁₀₋₁ (5.81/√10)
=-1.8± 2.26 (1.84)
= -1.8 ± 4.16
= (-5.96, 2.36)
Now,
There is a 95% confidence that the mean difference in age of maternal grand parents of high school students lies between - 5.96 and 2.36
(b) The age difference is calculated as the age of grand mother minus age of grand father. the point of estimate for the mean difference is as follows:
Xd = XGM - XGF
= 69.8 -71.6
=-1.8
Therefore, since the difference is negative, it can be said or determined that the age of the grandfather is older
Note: kindly find an attached copy of the complete question and table to this example below.
Answer:
1/5
Step-by-step explanation:
Hope this helps!
Answer:
76.2838
Step-by-step explanation:
E[X+Y] = E[X] + E[Y]
E[X] is the average of X or expectancy of X
E[Y] is the average or expectancy f Y
E[X] = 40P(student is in bus 1)+33P(student is in bus 2)+25P(student is in bus 3)+50P(student is in bus 4)=
40(40/148) + 33(33/148) + 25(25/148) + 50(50/148) = 39.2838
E[Y] = (number of students)/(number of drivers) = 148/4 = 37
So E[X+Y] = 39.2838 + 37 = 76.2838
Answer:
y=2(5 or x) +6 should be it
Step-by-step explanation:
Answer: 25%
Step-by-step explanation:
We know that 20 divided by 5 is 4, so 5 is one-fourth of 20 or 25%.