Ask question

Ask question

All categories

4 years ago

13

Use a model to solve. An average orange weighs 3/5 of a pound. Based on this average, how many oranges are in six pounds of oran

ges?

1 answer:

AnnyKZ [126]4 years ago

7 0

3/5x=6,
x=10 oranges

You might be interested in

Trey is 3 times older than his sister Kellit k stands for Kelli's age, which expression represents Trey's age?

ddd [48]

3 hope that can help you

4 0

3 years ago

The primary interest in designing a randomized block experiment is to: â€‹

zmey [24]

Answer:

e. none of these

Step-by-step explanation:

Primary interest in designing randomised block experiment is to : reduce the within treatment variation, to more easily detect differences between means.

A randomised block design involves the experimenter dividing subjects into subgroups known as blocks. The blocks are designed as to reduce the variability within the blocks, compared to variability between the blocks. This intra blocks less variation & inter blocks more variation, make blocks mean well represent their differences.

7 0

4 years ago

1. A right angled triangle has two shorter sides and one is twice as long as the other. The hypotenuse is 25 cm long. What are t

Semenov [28]

Step-by-step explanation:

The hypotenuse of a right-angled triangle = 25 cm

One side is twice as long as the other.

Let the other side is x.

First side = 2x

Using Pythagoras theorem to find the lengths of the shorter sides.

$x^2+(2x)^2=25^2\\\\x^2+4x^2=625\\\\5x^2=625\\\\x^2=125\\\\x=11.18\ cm$

So, the other side = 11.18 cm

First side = 2(11.18) = 22.36 cm

So, the lengths of the shorter sides are 11.18 cm and 22.36 cm.

7 0

3 years ago

What is the answer to (10y + 6)

schepotkina [342]

Answer:

2 ( 5 + 3 )

Step-by-step explanation:

Common factor

1 0 + 6 10y+6 2 ( 5 + 3 )

8 0

3 years ago

Read 2 more answers

What is the answer to this question ? Please answer !!

mylen [45]

$\text{Let}\ k:y=m_1x+b_1\ \text{and}\ k:y=m_2x+b_2,\ \text{then}\\\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\-------------------------\\\text{We have}\ 5x-y=-4.\ \text{Convert it to the slope-intercept form:}\\\\5x-y=-4\qquad\text{subtract 5x from both sides}\\\\-y=-5x-4\qquad\text{change the signs}\\\\y=5x+4\to m_1=5\to m_2=-\dfrac{1}{5}\\\\\text{Therefore we have}\ y=-\dfrac{1}{5}x+b.\\\\\text{The line passing through the point (-2, 2).}\\\text{Put the coordinates of the point to the equation:}$

$2=-\dfrac{1}{5}(-2)+b\\\\2=\dfrac{2}{5}+b\qquad\text{subtract}\ \dfrac{2}{5}\ \text{from both sides}\\\\1\dfrac{3}{5}=b\to b=\dfrac{8}{5}\\\\\text{Therefore we have the equation of a line in slope-intercept form:}\\\\y=-\dfrac{1}{5}x+\dfrac{8}{5}\\\\\text{Convert it to the standard form}\ Ax+By=C:\\\\y=-\dfrac{1}{5}x+\dfrac{8}{5}\qquad\text{multiply both sides by 5}\\\\5y=-x+8\qquad\text{add x to both sides}\\\\\boxed{x+5y=8}\to\boxed{[B]}$

8 0

3 years ago