This describes a parabolic path that starts at x=0 on a value of y = -5.1. That's when the rock is below ground in the hole. To find the answer we need to know the second x axis crossing. The first is when it is rising and reaches ground level, the second is after it peaks and falls back to the ground and lands. Using the quadratic formula I get the two zeros of this function to be about
x= 15.29, and 66.71. The rock then lands 66.71 feet from him horizontally.
Answer:
i’m struggling on this
Step-by-step explanation:
if anybody gets the answer please let me know
Answer:
Their y-intercepts are equal
Step-by-step explanation:
The y-intercept is the y-value where the function crosses the y-axis. In this problem, functions are presented in 2 ways: algebraically and in a table.
1) Fortunately, the algebraic equation is written in slope-intercept form; this means that intercept is easy to find. The slope-intercept form is y=mx+b, where b is the y-intercept. In function 1, the b value is 10.
2) Another way to describe the y-intercept is the y-value when x=0. So, the y-intercept on a table is wherever the x-value is 0. In this case, the first row represents when x=0. The table says that when x=0, y=10. This means that the y-intercept for function 2 is 10.
Since the y-intercept for both of the functions is 10, it can be said that the 2 functions have equivalent y-intercepts.
