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3 years ago

A student loses a uniforms

Mathematics

1 answer:

Anna35 [415]3 years ago

6 0

Answer:

Please ask a question so the community can help answer it and it has to be a school subject not a real life situation.

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Think about the expression (x-8)(x+4)

Softa [21]

Answer:

x*x +4*x-8*x -8*4

x^2+4x-8x-32

x^2-4x-32

4 0

3 years ago

An education firm measures the high school dropout rate as the percentage of 16 to 24 year olds who are not enrolled in school a

posledela

Answer:

The value of the test statistic $z = -0.6606$

Step-by-step explanation:

From the question we are told that

The high dropout rate is $\mu = 6.1$ % $= 0.061$

The sample size is $n = 1000$

The number of dropouts $x = 56$

The probability of having a dropout in 1000 people $\= x = \frac{56}{1000} = 0.056$

Now setting up Test Hypothesis

Null $H_o : p = 0.061$

Alternative $H_a : p < 0.061$

The Test statistics is mathematically represented as

$z = \frac{\= x - p}{\sqrt{\frac{p(1 -p)}{n} } }$

substituting values

$z = \frac{0.056 - 0.061}{\sqrt{\frac{0.061(1 -0.061)}{1000} } }$

$z = -0.6606$

6 0

3 years ago

I can't find the surface area, is this confusing me.

Fed [463]

<span>Find the area of two sides (Length*Height)*2 sidesFind the area of adjacent sides (Width*Height)*2 sidesFind the area of ends (Length*Width)*2 ends<span>Add the three areas together to find the surface area</span></span>

3 0

3 years ago

Read 2 more answers

Which of the following equations has exactly one solution?

shusha [124]

Answer:

Step-by-step explanation:

5a+4=9a+3-4a

5a-9a+4a=3-4

a=-1

6 0

2 years ago

An SRS of 25 recent birth records at the local hospital was selected. In the sample, the average birth weight was x = 119.6 ounc

Evgen [1.6K]

Answer:

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X}= \mu = 119.6$

And now for the deviation we have this:

$SE_{\bar X} = \frac{6.5}{\sqrt{25}}=1.3$

So then the correct answer for this caee would be:

c. 1.30 ounces.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X}= \mu = 119.6$

And now for the deviation we have this:

$SE_{\bar X} = \frac{6.5}{\sqrt{25}}=1.3$

So then the correct answer for this caee would be:

c. 1.30 ounces.

6 0

3 years ago