Answer:
0.0432M
Explanation:
We begin by writing a balanced equation for the reaction. This is illustrated below:
NaOH + HCl —> NaCl + H2O
From the equation above,
The number of mole of the acid (nA) = 1
The number of mole of the base (nB) = 1
Data obtained from the question include:
Vb (volume of the base) = 54mL
Cb (concentration of the base) = 0.1M
Va (volume of the acid) = 125mL
Ca ( concentration of the acid) =?
Using CaVa/CbVb = nA/nB, the concentration of the acid can easily be obtained as shown below:
CaVa/CbVb = nA/nB
Ca x 125 / 0.1 x 54 = 1
Cross multiply to express in linear form:
Ca x 125 = 0.1 x 54
Divide both side by 125
Ca = (0.1 x 54) / 125
Ca = 0.0432M
Therefore, the concentration of the acid is 0.0432M
The answer is D. Distilling.
Molar mass = 133.34 g/mol
Denser objects and substances experience a greater gravitational force acting upon their mass. This is why materials of different densities form layers. ... It is less dense than the Earth's crust, which is a solid. This is why the Earth's surface and atmosphere form distinct layers.
pls give brainliest if this helped :)
The volume of methanol necessary to prepare the antifreeze good for antifreeze solution is 3.2 L
<h3>Dilution formula</h3>
M₁V₁ = M₂V₂
Where
- M₁ is the molarity of stock solution
- V₁ is the volume of stock solution
- M₂ is the molarity of diluted solution
- V₂ is the volume of diluted solution
<h3>Data obtained from the question </h3>
- Molarity of stock solution (M₁) = 24.7 mol/L
- Volume of diluted solution (V₂) = 8 L
- Molarity of diluted solution (M₂) = 10 mol/L
- Volume of stock solution needed (V₁) = ?
<h3>How to determine the volume needed </h3>
The volume of the methanol necessary to prepare the solution can be obtained as illustrated below:
M₁V₁ = M₂V₂
24.7 × V₁ = 10 × 8
24.7 × V₁= 80
Divide both side by 24.7
V₁ = 80 / 24.7
V₁ = 3.2 L
Thus, the volume of methanol necessary to prepare the antifreeze good for antifreeze solution is 3.2 L
Learn more about dilution:
brainly.com/question/15022582
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