Answer:
There was 450.068g of water in the pot.
Explanation:
Latent heat of vaporisation = 2260 kJ/kg = 2260 J/g = L
Specific Heat of Steam = 2.010 kJ/kg C = 2.010 J/g = s
Let m = x g be the weight of water in the pot.
Energy required to vaporise water = mL = 2260x
Energy required to raise the temperature of water from 100 C to 135 C = msΔT = 70.35x
Total energy required = 

Hence, there was 450.068g of water in the pot.
Answer:
5
Explanation:
they are all significant All non-zero numbers ARE significant
<span>Elements are classified as metals, nonmetals, or metalloids according to their PHYSICAL PROPERTIES</span>
Answer:
134.397 Joules
Explanation:
Using the formula:
E = C × m × Δθ (where E is Energy, C is specific heat capacity and Δθ is change in temperature)
So E = 0.45×5.45×(79.8-25)
So E = 134.397 Joules