All categories

3 years ago

Plz help again. I will give 20 points again. NO BAD BOI/GURL

Mathematics

2 answers:

VladimirAG [237]3 years ago

8 0

Answer: So for the first drop-down its 22, and for the 2nd drop-down 2-3

Step-by-step explanation:

ivanzaharov [21]3 years ago

7 0

Good luck in school >

You might be interested in

Find the perimeter of the figure to the nearest hundredth.

Andru [333]

analyze data in picture

a 5*7 parallelogram and a half circle with a diameter of 5

5+7+7+5pi

is around

34.71

5 0

3 years ago

Stuart bought a sweater on sale for 30% off the original price and another 25% off the discounted price. If the original price o

s2008m [1.1K]

Answer:

15.75

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

How do you solve this to find r?

tatuchka [14]

Answer:

I honestly have no clue what the answer is.

Step-by-step explanation:

I honestly have no clue what the answer is.

6 0

3 years ago

Write the number white the same value as 32

frutty [35]

I think the answer is
0.32

7 0

4 years ago

A restaurant purchased kitchen equipment on January 1, 2017. On January 1, 2019, the value of the equipment was $14 comma 550

timama [110]

Answer:

$\frac{dV(t)}{dt} =$ - 1675.38

Step-by-step explanation:

In 2017, the vakue of the kitchen equipment was $14550

V(0)=$14550

Its value after then was modelled by $V(t)=14550e^{-0.158t$

We are required to find the rate of change in value on January 1, 2019

$V(t)=14550e^{-0.158t$

$\frac{dV(t)}{dt} =\frac{d}{dt}14550e^{-0.158t$

$\frac{dV(t)}{dt} =14550 \frac{d}{dt}e^{-0.158t$

$\\Let u= -0.158t,\frac{du}{dt}=-0.158$

$\frac{dV(t)}{dt} =14550 \frac{d}{du}e^u\frac{du}{dt}$

$\frac{dV(t)}{dt} =14550 X -0.158 e^{-0.158t}=-2298.9e^{-0.158t}$

In 2019, i.e. 2 years after, t=2

The rate of change of the value

$\frac{dV(t)}{dt} =-2298.9e^{-0.158X2}$

= $\frac{dV(t)}{dt} =-2298.9e^{-0.316}$ = - 1675.38

3 0

3 years ago