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3 years ago

Plz help again. I will give 20 points again. NO BAD BOI/GURL

Mathematics

2 answers:

VladimirAG [237]3 years ago

8 0

Answer: So for the first drop-down its 22, and for the 2nd drop-down 2-3

Step-by-step explanation:

ivanzaharov [21]3 years ago

7 0

Good luck in school >

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What is the percent increase between getting a high school scholarship and bachelors degree when high school scholarship is $421

gogolik [260]

Answer:

The percent increase between getting a high school scholarship and bachelor's degree is 59.14%.

Step-by-step explanation:

Given:

High school scholarship is $421.

Bachelor's degree is $670.

Now, to find the percent increase between a high school scholarship and bachelor's degree.

So, we get the amount of increase between a high school scholarship and bachelor's degree.

$670-421=249.$

Thus, the amount of increase = $249.

Now, to get the percent increase between a high school scholarship and bachelor's degree:

$\frac{249}{421}\times 100$

$=\frac{24900}{421}$

$=59.14\%.$

Therefore, the percent increase between getting a high school scholarship and bachelor's degree is 59.14%.

7 0

3 years ago

Find the smallest positive $n$ such that \begin{align*} n &\equiv 3 \pmod{4}, \\ n &\equiv 2 \pmod{5}, \\ n &\equiv

Alex777 [14]

4, 5, and 7 are mutually coprime, so you can use the Chinese remainder theorem right away.

We construct a number $x$ such that taking it mod 4, 5, and 7 leaves the desired remainders:

$x=3\cdot5\cdot7+4\cdot2\cdot7+4\cdot5\cdot6$

Taken mod 4, the last two terms vanish and we have

$x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod4$

so we multiply the first term by 3.

Taken mod 5, the first and last terms vanish and we have

$x\equiv4\cdot2\cdot7\equiv51\equiv1\pmod5$

so we multiply the second term by 2.

Taken mod 7, the first two terms vanish and we have

$x\equiv4\cdot5\cdot6\equiv120\equiv1\pmod7$

so we multiply the last term by 7.

Now,

$x=3^2\cdot5\cdot7+4\cdot2^2\cdot7+4\cdot5\cdot6^2=1147$

By the CRT, the system of congruences has a general solution

$n\equiv1147\pmod{4\cdot5\cdot7}\implies\boxed{n\equiv27\pmod{140}}$

or all integers $27+140k$ , $k\in\mathbb Z$ , the least (and positive) of which is 27.

3 0

3 years ago

An astronomical unit (AU) is the average distance between Earth and the sun. One AU is equal to approximately 150,000,000 km. As

Dimas [21]

Using scientific notation, it is found that the measure of one astronomical unit in kilometers is $1.5 \times 10^8$

A number in scientific notation is given by:

$a \times 10^b$

In which $a \in [1, 10)$

To realize the conversion from decimal to scientific notation, b is the number of decimal places the comma moves, being positive if to the left, negative if to the right.

In this problem, 1 AU = 150,000,000 km.

The comma has to move 8 places to the right, hence $b = 8$

Then, the measure is: $1.5 \times 10^8$

For more on scientific notation, you can check brainly.com/question/16394306

5 0

2 years ago

F(x) = 5x2 + 20x - 12 What is the vertex for this

kifflom [539]

Answer:

10+20x-12

20x-2

X=20-2

X=18

3 0

2 years ago

2x^2+x-1=2^are^x=-3/2 or x=

jenyasd209 [6]

The second answer is x=1

4 0

3 years ago