The information given in the question is not enough to determine the acidity of the solution. This is because, acidity can only be found with the equation: pH = -log [H+].
In order to determine the acidity of the solution, the half titration point value is needed, this will make it possible to determine the value of H30+. If the half point titration value is known, then Ka will be equivalent to pH and the value will be evaluated using the equation: - log (1.6 * 10^-10).
I do not see any possible answers that you have posted. But a good idea would be that it might have fossils, water currents, mud cracks, usually form in shallow seas. Hope this helps!
%Mass
Ar C = 12 g/mol, Mr C₄H₁₀ = 58 g/mol, Ar H = 1 g/mol
or
The standard Gibbs free energy of formation ΔGf° of Rb(s), H2(g) and Pb(s) are all zero. Similar to enthalpies of formation, the values of the standard Gibbs energies of formation are zero for the elements in their most stable forms at room conditions 298 Kelvin and one atmosphere pressure.
Answer:
The answer to your questions are given below
Explanation:
The answer to the questions given above can simply be obtained by writing the electronic configuration of each atom.
The electronic configuration of each atoms can be written as follow:
Fluorine, F (9) => 1s² 2s²2p⁵
Sodium, Na (11) => [Ne] 3s¹
Helium, He (2) => 1s²
Calcium, Ca (20) => [Ar] s²
Nitrogen, N (7) => 1s² 2s²2p³
Sulphur, S (16) => [Ne] 3s²3p⁴
