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3 years ago

Which system below has no solution?

Mathematics

2 answers:

Kisachek [45]3 years ago

8 0

Answer:

y=-4-* and y= 2 x-3

Step-by-step explanation:

alexandr402 [8]3 years ago

6 0

Answer:

y = 4^ and y = 2 x - 3

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3 years ago

The combined area of two squares is 80 square centimeters. Each side of one square is twice as long as a side of the other squar

olganol [36]

Answer:

The length of each side of the larger square is 8 centimeter.

Step-by-step explanation:

Given:

The combined area of two squares is 80 square centimeters. Each side of one square is twice as long as a side of the other square.

Now, to find the length of each side of the larger square.

Let $s$ be the length of the smaller square.

So, the length of the larger square = $2s.$

Now, we find the areas of the square by putting formula:

The area of smaller square = length² $=s^2.$

The area of larger square = (length)² $=(2s)^2=4s^2.$

As, given:

The combined area of two squares is 80 square centimeters.

According to question:

$s^2+4s^2=80\\5s^2=80$

So, dividing both sides by 5 we get:

$s^2=16$

Using square root on both sides we get:

$s=4\ centimeter.$

And, to get the length of each side of the larger square we substitute the value of $s$ :

$2s=2\times 4=8\ centimeter.$

The length of larger square = 8 centimeter

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3 years ago

HELP PLEASE, I will mark brainless

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3 years ago

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The answer is C.
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