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Makovka662 [10]
3 years ago
13

Critical thinking is important for evaluating which parts of advertisements are true and can be believed. true or false

Chemistry
2 answers:
BaLLatris [955]3 years ago
8 0

The correct answer is True.

It is true that critical thinking is important for evaluating which parts of advertisements are true and can be believed.

When an individual analyzes information objectively, uses the reason to understand something, applies logic to get information right, we say he/she is using critical thinking. This person does not believe the first thing it hears. To the contrary, he/she researches to check if its true or not. So yes, critical thinking is important for evaluating which parts of advertisements are true and can be believed.

Alborosie3 years ago
4 0
True , advertisements are made to trick consumers with mind tricks
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A metal tank containing hydrogen gas has a pressure gauge that reads 575 psi. What is causing the pressure inside of the tank?
alexandr1967 [171]

The  a metal tank containing hydrogen gas has a pressure gauge that reads 575 psi, 120  pressure inside of the tank.

What is pressure gauge?

A device used to measure a fluid's (liquid or gas') state by calculating the force the fluid would apply to a unit area if it were at rest.

What is pressure?

The force of all gas particle/wall collisions divided by the surface area of the wall is the definition of pressure (P): One of the fundamental quantifiable variables.

Therefore, a metal tank containing hydrogen gas has a pressure gauge that reads 575 psi, 120  pressure inside of the tank.

Learn more about pressure gauge from the given link.

brainly.com/question/13292088

#SPJ4

5 0
1 year ago
1. (a) Write the two electrochemical half reactions for ethanol (C2H5OH) direct electrochemical conversion in a fuel cell with a
Natalka [10]

Answer:

(a) Two electrochemical half reactions for ethanol (C_{2}H_{5}OH) is written below

      C_{2}H_{5} + 60 ⇒ 2CO_{2} + 3H_{2}O + 12e^{-} (anode)

      3O_{2} + 12e^{-} ⇒ 60^{=} (Cathode)

(b) The direct oxidation of the fuel will occur in a solid oxide fuel cell but we have to compete with other sets of chemical electrochemical reaction such as water-gas-shift reaction

      CO + H_{2}O ⇆ CO_{2}  + H_{2}(WGSR)

(c) The electrochemical half reaction that could convert ethanol directly into a fuel cell that conducts hydrogen ions is shown below

C_{2}H_{5}OH + 3H_{2}O  ⇒  2CO_{2} + 12H^{+} + 12e^{-} (anode)

3O_{2} + 12H^{+} + 12e^{-} - 6H_{2}O (Cathode)

C_{2} H_{5} OH + 3O_{2}  ⇒  3H_{2}O + 2CO_{2}

(d) The half reactions that would be required are shown below

C_{2}H_{5} OH + 12OH^{-}  ⇒  CO_{2} + 9H_{2}O  + 12e^{-}  (anode)

3O_{2} + 6H_{2}O + 12e^{-}  ⇒  12OH^{-}  (Cathode)

C_{2}H_{5}OH + 3O_{2}  ⇒  3H_{2}O  + 2CO_{2}

8 0
4 years ago
Choose the statement that is NOT true.
NISA [10]

Answer:

More than 50% of the 100 billion stars in the Milky Way galaxy have at least one planet orbiting.

Explanation:

This is False so this would be your Answer

6 0
3 years ago
Read 2 more answers
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
Salsk061 [2.6K]

Answer:

kp= 3.1 x 10^(-2)

Explanation:

To solve this problem we have to write down the reaction and use the ICE table for pressures:

                                2SO2      +        O2         ⇄              2SO3

Initial                      3.4 atm           1.3 atm                         0 atm

Change                    -2x                    - x                                + 2x

Equilibrium            3.4 - 2x            1.3 -x                          0.52 atm

In order to know the x value:

2x = 0.52

x=(0.52)/2= 0.26

                               2SO2             +          O2              ⇄              2SO3

Equilibrium        3.4 - 0.52                1.3 - 0.26                     0.52 atm

Equilibrium        2.88 atm                 1.04 atm                      0.52 atm

with the partial pressure in the equilibrium, we can obtain Kp.

Kp=\frac{PSO3^2}{PSO2^2 PO2}=\frac{(0.52)^2}{(2.88)^2(1.04)}=0.03135

8 0
3 years ago
If 2.68 g of benzaldehyde are involved with the mixed aldol condensation reaction, how many moles of benzaldehyde are present? R
Zielflug [23.3K]

Answer:

The number of moles of benzaldehyde = 0.0253 moles

Explanation:

The molecular formula of benzaldehyde is C₇H₆O

Its molecular mass is calculated from the atomic masses of the constituent atoms.

C = 12.0 g: H = 1.0 g; O = 16.0 g

Molecular mass = ( 12 * 7) + (1 * 6) + (16 * 1) = 106.0 g/mol

Number of moles of  substance = mass of substance/ molar mass of the substance

mass of benzaldehyde = 2.68; molar mass = 106.0 g/mol

Number of moles of benzaldehyde = 2.68 g/ 106 g/mol = 0.0253 moles

Therefore, the number of moles of benzaldehyde = 0.0253 moles

8 0
3 years ago
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