CO + 2 H2 → CH3OH
<span> find # of mols in each reactants, </span>
<span>152500 g CO x 1 mol CO / 28.01g CO = 5444 mol CO </span>
<span>24500 g H2 x 1 mol H2 / 2.02 g H2 = 12129 mol H2 </span>
<span>mol ratio between CO and H2 is 1:2, which means each mol of production of CH3OH need 1 mol of CO and 2 mol of H. </span>
<span>H2 is enough to produce 6064 mols of CH3OH but there are only 5444mol of CO. </span>
<span>5444 mol CH3OH x molar mass of CH3OH / 1 mol CH3OH </span>
<span>= 174371 g = 174.4 kg</span>
Soild because the liquid and gas are contanly moving and rearanging while soild tries to stay the same
Balance Chemical Equation is,
<span>CaO </span>₍s₎ <span>+ CO</span>₂ ₍g₎ <span>→ CaCO</span>₃ ₍s₎
According to Equation
56.07 g of CaO when reacted with excess CO₂ produces = 100.08 g of CaCO₃.
Then,
1.8 g of CaO is reacted with excess CO₂ = X g of CaCO₃ will produce.
Solving for X,
X = (100.08 g × 1.8 g) ÷ 56. 07 g
X = 3.21 g of CaCO₃
Answer:- 324.3 grams.
Solution:- We have been given with 6.0 moles of nitrous acid and asked to calculate it's grams. Moles to grams is a unit conversion and for doing this conversion we multiply the given moles by the molar mass of the compound.
Molar mass is the formula mass and to calculate this the atomic masses of each atom are multiplied by their respective subscripts that is the number of the atom in the compound .
For example, has one nitrogen atom and one oxygen atom. So, the molar mass of this is = atomic mass of N + 2(atomic mass of O)
= 14 + 2(16)
= 14 + 32
= 46 gram per mol
gram per mol is the unit of molar mass. So, the molar mass of is 46 grams per mol.
Let's calculate the molar mass of nitrous acid using the same concept.
molar mass of [ = 1 + 14 + 2(16)
= 1 + 14 + 32
= 47 grams per mol
Now, 6.9 moles of nitrous acid could easily be converted to grams as:
= 324.3 g
Hence, the mass of 6.9 moles of nitrous acid is 324.3 grams.