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First write and balance the equation, being:
CaCO3 - CaO + CO2
Then, using the periodic table, find the molecular masses of CaCO3 and of CaO, finding their ratio. That will be 100g:56g or 0.1kg:0.056kg. Since you have 4.7kg of CaCO3, it corresponds to Xkg of CaO. Making x the subject, it should be X= 4.7*0.056/100=0,002632
Answer:
1. Filtration. One of the simplest methods used to separate mixtures is filtration.
2. Distillation. When one compound is dissolved in another, or when two liquids are mixed together, the most commonly used method to separate them is distillation.
Explanation:
Have a nice day.
Answer: Explanation:
With an increase in temperature, there is typically an increase in the molecular interchange as molecules move faster in higher temperatures. The gas viscosity will increase with temperature. ... With high temperatures, viscosity increases in gases and decreases in liquids, the drag force will do the same.
The increase in temperature causes the kinetic or thermal energy to increase and the molecules become more mobile. The attractive binding energy is reduced and therefore the viscosity is reduced.
liquids show a reduction in viscosity with increasing temperature. With high temperatures, viscosity increases in gases and decreases in liquids, the drag force will do the same.
4.743 x s-1 is the value of the rate constant.
<h3>What is an Arrhenius equation?</h3>
The Arrhenius equation describes the relationship between the rate of reaction and temperature for many physical and chemical reactions.
As per Arrhenius equation,
k = Ae-Ea÷RT
T = 227 = 500.15 K
R = 0.008314 kJ/K mol
Ea = 150 kJ/mol
Ea÷RT
= 150÷(0.008314 x 500.15)
= 36.073
k = Ae-36.073 = (2.2 x s-1) (2.156 x )
k = 4.743 x s-1
So, the correct answer is option d) i.e. 4.7 x s-1
As per Arrhenius equation,
k = Ae-Ea/RT
T = 227 = 500.15 K
R = 0.008314 kJ/K mol
Ea = 150 kJ/mol
Ea÷RT = 150÷(0.008314 x 500.15) = 36.073
k = Ae-36.073 = (2.2 x s-1)(2.156 x )
k = 4.743 x s-1
Hence, 4.743 x s-1 is the value of the rate constant.
Learn more about the Arrhenius equation here:
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