Answer:
// here is code in c++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main() {
// variable
int num;
int tot_sum=0;
cout<<"enter a number: ";
// read the value of n
cin>>num;
// check the multiple of 2 or 5 from 1 to n
for(int x=1;x<=num;x++)
{
// if multiple of 2 or 5 then add them
if(x%2==0 ||x%5==0)
{
tot_sum=tot_sum+x;
}
}
// print the sum
cout<<"sum of multiple of 2 or 5 is:"<<tot_sum<<endl;
return 0;
}
Explanation:
Read the number "n" from user.Check every number from 1 to n, if it is a multiple of 2 or 5 then add them to "tot_sum".When the for loop end, "tot_sum" will have sum of all the number which are either multiple of 2 or 5.Print the sum.
Output:
enter a number:11
sum of multiple of 2 or 5 is:35
C. She would have to resort to trial and errors to find a matching exponent
#This is a way without a loop
friends = list(map(str,input("Enter Names: ").split()))
print(sorted(friends))
#This is a way with a loop (for&&while)
friends = list(map(str,input("Enter Names: ").split()))
cool = True
while cool:
cool = False
for i in range(len(friends)-1):
if friends[i] > friends[i+1]:
coo = friends[i]
friends[i] = friends[i+1]
friends[i+1] = coo
cool = True
print(friends)
<span>It is a logical, systematic search for the source of a problem in order to solve it, and make the product or process operational again.Troubleshooting is needed to identify the symptoms. ...Troubleshooting is the process of isolating the specific cause or causes of the symptom.</span>
