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slava [35]
3 years ago
6

Please answer my question

Physics
2 answers:
hram777 [196]3 years ago
7 0

Answer:

Answer is (b) Mercury, venus and Mars.

Flura [38]3 years ago
3 0

Explanation:

i think b is correct!!

;-) :-) :-) :-)

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A 148 g ball is dropped from a tree 11.0 m above the ground. With what speed would it hit the ground
forsale [732]

Answer:

14.68m/s

Explanation:

As per the question, the data provided is as follows

Mass = M = 0.148 kg

Height = h = 11 m

Initial velocity = U = 0 m/s

Final velocity = V

Gravitational force = F

Mass = M

Based on the above information, the speed that hit to the ground is

As we know that

Work to be done = Change in kinetic energy

F ( S) = (\frac{1}{2} ) M ( V^2 - U^2 )

M g h = (\frac{1}{2} ) M ( V^2 - U^2 )

g h = (\frac{1}{2} ) ( V^2 - U^2 )

V^2 - U^2 = 2gh

V^2 - 0 = 2gh

V = \sqrt{2 g h}

= \sqrt{2\times9.8\times11}

= 14.68m/s

7 0
3 years ago
From
madreJ [45]

Answer:

From C to D, kinetic energy is transformed into

gravitational potential energy.

4 0
3 years ago
A force of 100 N will exert the greatest pressure on an area of
lbvjy [14]

Answer:

It will apply the greatest pressure of an area of 1.

Explanation:

To find pressure use the formula P = F/A

P = 100/1

P = 100

5 0
3 years ago
Read 2 more answers
A water bug is suspended on the surface of a pond by surface tension (water does not wet the legs). The bug has six leg, and eac
Crazy boy [7]

Answer:

m = 2.2 x 10⁻⁴ kg = 0.22 g

Explanation:

The surface tension of water is 0.072 N/m. So in order for the bug to avoid sinking, its weight per unit length of contact must be no more than the surface tension of water. Therefore,

Weight\ of bug\ per\ unit\ length = Surface\ Tension\ of\ Water\\\frac{mg}{L} = Surface\ Tension\ of Water\\m = \frac{(Surface\ Tension\ of\ Water)(L)}{g}

where,

m = mass of bug = ?

g = acceleration due to gravity = 9.81 m/s²

L = Contact length = (contact length of each leg)(No. of Legs) = (5 mm)(6)

L = 30 mm = 0.03 m

Therefore,

m = \frac{(0.072\ N/m)(0.03\ m)}{9.81\ m/s^{2}} \\

<u>m = 2.2 x 10⁻⁴ kg = 0.22 g</u>

8 0
3 years ago
A constant amount of charge passes through a conductor. How is current affected if the same amount of charge passes in less time
baherus [9]

Answer:

B. The current increases.

Explanation:

As we know that rate of flow of charge through the conductor is known as electric current

So we have

i = \frac{q}{t}

here we know that charge Q flowing through the conductor is constant while the time in which it passes through it is decreased

so we can say that the ratio of charge and time will increase

so here we have

i = increased

So correct answer will be

B. The current increases.

4 0
4 years ago
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